在FIND_IN_SET中使用MySQL IN条件

Question

我有一个查询，我使用一个相当密集的WHERE IN子句来获取与玩家相关的ID列表。

SELECT p.name, 
    0a.stat_value 
FROM leaderheadsplayers p 
LEFT JOIN leaderheadsplayersdata_alltime 0a 
ON 0a.player_id = p.player_id 
AND 0a.stat_type = 'kills' 
WHERE p.player_id IN 
    (SELECT player_id 
    FROM 
    (SELECT 0a.player_id 
    FROM leaderheadsplayersdata_alltime 0a 
    WHERE 0a.stat_type = 'kills' 
    ORDER BY 0a.stat_value DESC LIMIT 0, 
     20 
    ) 1a 
) 

的问题是，我想用FIND_IN_SET没有再做从IN子句密集的查询，以保持这些ID的从IN子句的顺序在我的最终结果。 事情是这样的：

SELECT p.name, 
    0a.stat_value 
FROM leaderheadsplayers p 
LEFT JOIN leaderheadsplayersdata_alltime 0a 
ON 0a.player_id = p.player_id 
AND 0a.stat_type = 'kills' 
WHERE p.player_id IN 
    (SELECT player_id 
    FROM 
    (SELECT 0a.player_id 
    FROM leaderheadsplayersdata_alltime 0a 
    WHERE 0a.stat_type = 'kills' 
    ORDER BY 0a.stat_value DESC LIMIT 0, 
     20 
    ) 1a 
) 
ORDER BY FIND_IN_SET(p.player_id, result_from_in_clause) 

这是我的电流输出：

player_id | stat_value 
3 | 304 
5 | 507 
4 | 208 

这就是我想：

player_id | stat_value 
5 | 507 
3 | 304 
4 | 208 

Answer 1

简单order by应该能够能够做到这一点：

SELECT p.name, 
    0a.stat_value 
FROM leaderheadsplayers p 
LEFT JOIN leaderheadsplayersdata_alltime 0a 
ON 0a.player_id = p.player_id 
AND 0a.stat_type = 'kills' 
WHERE p.player_id IN 
    (SELECT player_id 
    FROM 
    (SELECT 0a.player_id 
    FROM leaderheadsplayersdata_alltime 0a 
    WHERE 0a.stat_type = 'kills' 
    ORDER BY 0a.stat_value DESC LIMIT 0, 
     20 
    ) 1a 
) 
order by 
    0a.stat_value, p.player_id;