排序规则的非法组合（utf8_general_ci，COERCIBLE）和（latin1_swedish_ci，隐含的）

Question

谁能帮我，我怎么能解决这个错误

Illegal mix of collations (utf8_general_ci,COERCIBLE) and (latin1_swedish_ci,IMPLICIT) for operation 'locate' 

我已执行我的存储过程在Server1和它的做工精细，但它会在服务器2上引发错误。我已经检查了两台服务器上的所有表和存储过程，它们都是一样的。

任何人都可以帮助我解决这个问题和解决方案。

这里是存储过程。

DELIMITER $$ 

DROP PROCEDURE IF EXISTS `UPDATEPASSWORD` $$ 
CREATE DEFINER=`root`@`localhost` PROCEDURE `UPDATEPASSWORD`(IN empn CHAR(9), IN oldpassword VARCHAR(255), IN newpassword VARCHAR(255)) 
main:BEGIN 
DECLARE diction INT; 
DECLARE prevpass INT; 
DECLARE len INT; 
DROP TABLE IF EXISTS passwordstatus; 
CREATE TEMPORARY TABLE passwordstatus 
(
    `passwordstatus` VARCHAR(127) 
); 

PREPARE stmt1 FROM "select count(seqid) into @diction 
        from dictionary where instr(?,word)>0 or instr(REVERSE(?),REVERSE(word))>0 "; 
SET @a = newpassword; 
SET @b = newpassword; 
EXECUTE stmt1 USING @a,@b; 
DEALLOCATE PREPARE stmt1; 
IF @diction > 0 THEN 
    START TRANSACTION; 
    PREPARE stmt1 FROM "INSERT INTO passwordstatus VALUES (?)"; 
    SET @a = "PASSWORD CONTAINS COMMONLY USED WORDS"; 
    EXECUTE stmt1 USING @a; 
    DEALLOCATE PREPARE stmt1; 
    COMMIT; 
    SELECT * FROM passwordstatus; 
    LEAVE main; 
END IF; 

PREPARE stmt1 FROM "select count(seqid) into @prevpass 
        from prevpass where (instr(sha1(?),passwd)>0 or instr(REVERSE(sha1(?)),REVERSE(passwd))>0)and empno = ?"; 
SET @a = newpassword; 
SET @b =empn; 
EXECUTE stmt1 USING @a, @a, @b; 
DEALLOCATE PREPARE stmt1; 
IF @prevpass > 0 THEN 
    START TRANSACTION; 
    PREPARE stmt1 FROM "INSERT INTO passwordstatus VALUES (?)"; 
    SET @a = "PASSWORD CONTAINS PREVIOUSLY USED PASSWORDS"; 
    EXECUTE stmt1 USING @a; 
    DEALLOCATE PREPARE stmt1; 
    COMMIT;  
    SELECT * FROM passwordstatus; 
    LEAVE main; 
END IF; 

PREPARE STMT1 FROM " SELECT COUNT(seqid) INTO @prevpass FROM prevpass where empno = ? "; 
SET @a = empn; 
EXECUTE STMT1 USING @a; 
DEALLOCATE PREPARE STMT1; 
START TRANSACTION; 
IF @prevpass = 6 THEN 
    PREPARE STMT1 FROM "DELETE FROM prevpass WHERE EMPNO = ? ORDER BY seqid LIMIT 1"; 
    SET @a = empn; 
    EXECUTE STMT1 USING @a; 
    DEALLOCATE PREPARE STMT1; 
END IF; 
PREPARE STMT FROM " UPDATE emppass SET passwd = sha1(?),lastupdate = now() WHERE empno = ? "; 
SET @a = newpassword; 
SET @b = empn; 
EXECUTE STMT USING @a,@b; 
DEALLOCATE PREPARE STMT; 
PREPARE STMT1 FROM " INSERT INTO prevpass (empno,passwd,createdate) VALUES (?,sha1(?),now())"; 
SET @a = empn; 
SET @b = newpassword; 
EXECUTE STMT1 USING @a,@b; 
DEALLOCATE PREPARE STMT1; 
PREPARE stmt1 FROM "INSERT INTO passwordstatus VALUES (?)"; 
    SET @a = "PASSWORD UPDATED SUCCESSFULLY"; 
    EXECUTE stmt1 USING @a; 
    DEALLOCATE PREPARE stmt1; 
COMMIT; 
SELECT * FROM passwordstatus; 

END $$ 

DELIMITER ; 

Answer 1

尝试在每个参数前都有一个BINARY命令。

SHA1(BINARY ?) 
BINARY passwd 

Answer 2

查询您正在执行。两台服务器上表的

检查表校对：

，我可以看到现在，你可以做到这一点

select table_name, table_collation 
    from information_schema.tables 
where table_schema = database(); 

并检查列的排序规则：

select * 
from information_schema.columns 
where table_schema = database() 
    and collation_name is not null 
    and collation_name not like 'utf8%'; 

可能这可以帮助你。