好吧...我需要遍历任意长度的字符串。因为我不知道该如何解释这也很好,我的意思是这样的:通过数字的未知长度的字母进行迭代
def zip(string1,string1):
...
当与"a"
和"ad"
称它会返回一个列表:
>>>zip("a","ad")
["a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z","aa","ab","ac","ad"]
我已经尝试使用map(chr,range(ord('a'),ord('nb')+1))
但我得到TypeError: ord() expected a character, but string of length 2 found
,我不知道该从哪里出发。有任何想法吗?
起初我有点困惑,因为zip是一种实际的python方法。 – Fallenreaper