$str = "Data = [ {"name": "test","Address": "UK" "currency": "£" },{"name": "test2","Address": "US" "currency": "$" },{"name": "test","Address": "eur" "currency": "E" }
我要显示所有地址什么是匹配单行与多重匹配的正则表达式?
其不支持多行字符串。这一切都一个字符串
请在这个
感谢帮助, TREEĴ
$str = "Data = [ {"name": "test","Address": "UK" "currency": "£" },{"name": "test2","Address": "US" "currency": "$" },{"name": "test","Address": "eur" "currency": "E" }
我要显示所有地址什么是匹配单行与多重匹配的正则表达式?
其不支持多行字符串。这一切都一个字符串
请在这个
感谢帮助, TREEĴ
这应该工作:
while ($str =~ /\"Address\":\S+\"(.*?)\"/g) {
print "Address = $1\n";
}
你的字符串是JSON! Treat it as such!
编辑:我是个白痴,无法分辨问题标记为perl而不是PHP :-)链接被修正。
修正,棒材'数据='开头。你从哪里得到数据? – fredley 2010-08-31 15:58:37
类似:
my $str = q(Data = [ {"name": "test","Address": "UK" "currency": "£" },{"name": "test2","Address": "US" "currency": "$" },{"name": "test","Address": "eur" "currency": "E" });
my @addresses = $str =~ /"Address":\s*"([^"]*)"/g;
print "@addresses\n";
HTH,
保罗
(PS:后实际的代码,而不是伪代码...)
你通过使用正确的工具来完成这项工作。在这种情况下,你修复损坏的JSON用正则表达式,然后使用JSON
得到数据:
#!/usr/bin/perl
use strict;
use warnings;
use JSON;
my $input = <DATA>;
my ($json) = $input =~ /DATA = (.*)/;
my $data = decode_json $json;
for my $record (@$data) {
print "$record->{name} has address $record->{Address}\n";
}
__DATA__
DATA = [ {"name": "test", "Address": "UK", "currency": "£" }, {"name": "test2", "Address": "US", "currency": "$" }, {"name": "test", "Address": "eur", "currency": "E" } ]
不,g修饰符确保获得所有匹配! – ennuikiller 2010-08-31 16:07:09
对不起我的错误! – Tree 2010-08-31 16:08:37