我只是想检查用户名是否已经存在,基本的想法是,当表单发送时,我的ajax代码将连接到checkUsername.php,并且checkUsername.php将会去我的数据库并检查用户名已经存在,并返回一个跨度。为什么我的ajax代码没有运行?
$.ajax({
url: "checkUsername.php",
type: "post",
data: {"usernameCheck": v1},
dataType:"text",
success:function(data){
alert("system avaliable!!");
if($("#status-not-available").val(data) == "no"){
$('#username').css({'border' : '4px solid red'});
checkUsername = false;
}
else{
$('#username').css({'border' : '4px solid white'});
}
},
fail:function(data){
alert("system not avaliable");
},
});
PHP:
$database = new SQLite3('myDatabase.db'); //setup connection
$usernameCheck = $_POST['usernameCheck']; //get the username they input
$stmt = $database->prepare("SELECT * FROM users WHERE username = :usernameCheck");
$stmt->bindValue(':usernameCheck',$usernameCheck,SQLite3_TEXT);
$row = $stmt->execute()->fetchArray();
if(isset($row['username'])){
echo "<span class='status-not-available'>no</span>";
}
else{
echo "<span class='status-not-available'>yes</span>";
}
你有什么错误或什么? – Mazz
_什么东西必须发生......? – Tom
v1是什么?在请求的正文中? –