mySQL查询 - 简单的数学问题

Question

我有2个电话号码为每个人。其中有些人只有电话填写其他人只有电话2填写，有些人都有。

我试图找其他人用同一个电话号码，无论是电话=电话，电话= telephone2，telephone2 =电话，telephone2 = telephone2

问题是，如果telephone1为空，然后我现有的代码将如果电话或电话2为空，则将其与具有电话号码的下一个人相匹配，而不管匹配如何。我需要添加什么代码。

function getothers($tid,$criteria,$telephone,$telephone2,$elector){ 
       global $dbh; 
       $tid = '-TID'.$tid; 
       $sql = "SELECT * FROM electors 
WHERE (telephone > 0 OR telephone2 > 0) 
AND records NOT RLIKE '$tid' 
AND (telephone IN ('$telephone','$telephone2') 
OR telephone2 IN ('$telephone','$telephone2')) 
AND ID != '$elector' LIMIT 10"; 
       return $dbh->query($sql); 
      } 

Answer 1

SELECT T_el.* 
FROM (electors AS T_el) LEFT JOIN (electors AS T_dup) 
ON (T_el.ID!=T_dup.ID 
    AND (
    (T_el.telephone IS NOT NULL AND (T_el.telephone=T_dup.telephone OR T_el.telephone=T_dup.telephone2)) 
    OR 
    (T_el.telephone2 IS NOT NULL AND (T_el.telephone2=T_dup.telephone OR T_el.telephone2=T_dup.telephone2)) 
    ) 
) 
WHERE T_dup.ID IS NOT NULL 
GROUP BY T_el.ID 

Answer 2

function getothers($tid,$criteria,$telephone,$telephone2,$elector){ 
      global $dbh; 
      $tid = '-TID'.$tid; 
      $sql = "SELECT * FROM electors WHERE (telephone > 0 AND telephone IN ('$telephone','$telephone2')) OR (telephone2 > 0 AND telephone2 IN ('$telephone','$telephone2')) $criteria AND records NOT RLIKE '$tid' AND ID != '$elector' LIMIT 10"; 
      return $dbh->query($sql); 
     }