2011-11-04 138 views
0

我有一个XSD文件,它决定了我的引擎可以与其他插件(使用不同语言编写,如Delphi)通信的模式。我使用.Net提供的XSD工具从XSD文件中获取C#类。asp.net web服务返回空对象

插件返回一个XML字符串,然后我将其反序列化到由XSD工具生成的类中。

一切都很好,直到那里,但是当我通过Web服务传递到客户端的类的数组时,该数组包含一个元素,这是很好,但该对象中的每个字段为null或设置为其默认值。

任何想法为什么会发生这种情况?

我也尝试发送虚拟数据,而不是通常从插件检索数据,但仍然返回的对象是空的。

这是由XSD工具生成的类:

using System.Xml.Serialization; 


/// <remarks/> 
[System.Xml.Serialization.XmlRootAttribute(Namespace="", IsNullable=false)] 
public class BookingQueryResponse { 

    /// <remarks/> 
    public int ErrorCode; 

    /// <remarks/> 
    public string ErrorString; 

    /// <remarks/> 
    public int BookingQueryID; 

    /// <remarks/> 
    public int DestinationID; 

    /// <remarks/> 
    public string DestinationName; 

    /// <remarks/> 
    [System.Xml.Serialization.XmlElementAttribute(DataType="date")] 
    public System.DateTime ArrivalDate; 

    /// <remarks/> 
    [System.Xml.Serialization.XmlElementAttribute(DataType="date")] 
    public System.DateTime DepartureDate; 

    /// <remarks/> 
    public int CurrencyID; 

    /// <remarks/> 
    public string CurrencyISO; 

    /// <remarks/> 
    public string CurrencySymbol; 

    /// <remarks/> 
    public int LangID; 

    /// <remarks/> 
    public string LangCode; 

    /// <remarks/> 
    [System.Xml.Serialization.XmlElementAttribute("HotelQuotePackages")] 
    public HotelQuotePackage[] HotelQuotePackages; 
} 

/// <remarks/> 
public class HotelQuotePackage { 

    /// <remarks/> 
    public string PackageGuid; 

    /// <remarks/> 
    public string PackageName; 

    /// <remarks/> 
    public string PluginGuid; 

    /// <remarks/> 
    public int ResortID; 

    /// <remarks/> 
    public string ResortName; 

    /// <remarks/> 
    public int HotelID; 

    /// <remarks/> 
    public string HotelName; 

    /// <remarks/> 
    public int HotelRatingID; 

    /// <remarks/> 
    public string HotelRatingName; 

    /// <remarks/> 
    public string HotelNarrative; 

    /// <remarks/> 
    public System.Double MapLongitude; 

    /// <remarks/> 
    public System.Double MapLatitude; 

    /// <remarks/> 
    public string HotelRemark; 

    /// <remarks/> 
    public string OfferText; 

    /// <remarks/> 
    [System.Xml.Serialization.XmlElementAttribute("HotelRoomQuotes")] 
    public HotelRoomQuote[] HotelRoomQuotes; 

    /// <remarks/> 
    [System.Xml.Serialization.XmlElementAttribute("HotelImages")] 
    public HotelMediaImage[] HotelImages; 
} 

/// <remarks/> 
public class HotelRoomQuote { 

    /// <remarks/> 
    public int RoomNumber; 

    /// <remarks/> 
    [System.Xml.Serialization.XmlElementAttribute("RoomQuotes")] 
    public RoomQuote[] RoomQuotes; 
} 

/// <remarks/> 
public class RoomQuote { 

    /// <remarks/> 
    public string Guid; 

    /// <remarks/> 
    public int AdultPax; 

    /// <remarks/> 
    public int ChildPax; 

    /// <remarks/> 
    public int InfantPax; 

    /// <remarks/> 
    public string RoomTypeName; 

    /// <remarks/> 
    public string RoomTypeDesc; 

    /// <remarks/> 
    public int BoardBasisID; 

    /// <remarks/> 
    public string BoardBasisName; 

    /// <remarks/> 
    public System.Double CostForStay; 

    /// <remarks/> 
    public string Remarks; 

    /// <remarks/> 
    [System.Xml.Serialization.XmlElementAttribute("DayRates")] 
    public DayRate[] DayRates; 
} 

/// <remarks/> 
public class DayRate { 

    /// <remarks/> 
    [System.Xml.Serialization.XmlElementAttribute(DataType="date")] 
    public System.DateTime Date; 

    /// <remarks/> 
    public System.Double Rate; 
} 

/// <remarks/> 
public class HotelMediaImage { 

    /// <remarks/> 
    public string HotelImage; 

    /// <remarks/> 
    public int ImageTypeID; 

    /// <remarks/> 
    public string ImageType; 
} 

,只是为了测试Web服务,我所做的是这样的:

return return new BookingQueryResponse[1] { new BookingQueryResponse() { ArrivalDate = DateTime.Now.Date, DestinationName = "Malta" } }; 
+0

它听起来像在xml中的不匹配和类型......很难说没有具体细节虽然(即C#和XML) –

+0

看看你的对象名称空间(而不是c#命名空间,但xml名称空间指定的属性XmlType )在你生成的类和你的xml文件中,它们必须匹配! –

+0

@Marc Gravell我编辑了这个问题,包括生成的c#类,如果它有帮助。 – Jonny

回答

0

请张贴的XSD。由于你的类看起来很好,我最初的猜测是它的XSD和C#命名空间之间的类型(名称空间)不匹配。

相关问题