2013-02-08 45 views
0

我试图建立从String一个STGroup但抱怨无效字符和失踪模板:什么是从字符串构建组的正确stringtemplate组语法?

final String templates = "a(x) ::= <li>$x.fname$ $x.lname$</li>\n" + 
          "b(persons) ::= <ul>$persons:a()$</ul>\n"; 
    final STGroup grp = new STGroupString("mysource", templates, '$', '$'); 

这里是它喷出了误差修改:

mysource 1:10: invalid character '<' 
mysource 1:10: missing template at 'li' 
mysource 1:12: invalid character '>' 
mysource 1:13: invalid character '$' 
mysource 1:10: garbled template definition starting at 'li' 
mysource 1:14: garbled template definition starting at 'x' 
mysource 1:21: invalid character '$' 
mysource 1:23: invalid character '$' 
mysource 1:16: garbled template definition starting at 'fname' 
mysource 1:24: garbled template definition starting at 'x' 
mysource 1:31: invalid character '$' 
mysource 1:33: invalid character '<' 
mysource 1:34: invalid character '/' 
mysource 1:26: garbled template definition starting at 'lname' 
mysource 1:36: invalid character '>' 
mysource 1:34: garbled template definition starting at 'li' 
mysource 2:16: invalid character '<' 
mysource 2:16: missing template at 'ul' 
mysource 2:18: invalid character '>' 
mysource 2:19: invalid character '$' 
mysource 2:16: garbled template definition starting at 'ul' 
mysource 2:20: garbled template definition starting at 'persons' 
mysource 2:31: invalid character '$' 
mysource 2:33: invalid character '<' 
mysource 2:34: invalid character '/' 
mysource 2:36: invalid character '>' 
mysource 2:34: missing '::=' at 'ul' 
mysource 2:34: missing template at 'ul' 
mysource 2:28: redefinition of template a 
mysource 2:34: garbled template definition starting at 'ul' 

我想使用$作为我的分隔符,能够呈现这些模板的正确格式是什么?

回答

0

我想出了一个解决方案的程序与解答一些相关的问题和一些实验:

STGroup grp = new STGroup('$', '$'); 
    final CompiledST templateA = grp.defineTemplate("a", "<li>$it.fname$ $it.lname$</li>"); 
    templateA.addArg(new FormalArgument("it")); 
    final CompiledST templateB = grp.defineTemplate("b", "<ul>$list:a()$</ul>"); 
    templateB.addArg(new FormalArgument("list")); 
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