SQL，OPENXML和DateTime对话

Question

我已经继承了大量的存储过程，它们将一个XML块作为其唯一参数，然后作者将其破解（使用OPENXML），然后更新一行。

我遇到的一个问题，同时更新具有datetime列一个表，下面是数据的一个片段，目前失败：

declare @stuff nvarchar (max); 

set @stuff = 
'<Booking xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> 
    <UpdatedDateTime>2009-08-14T15:32:09.7240556+01:00</UpdatedDateTime> 
</Booking>'; 

declare @iDoc int; 

exec sp_xml_preparedocument @idoc OUTPUT, @stuff; 

SELECT UpdatedDateTime 
    FROM 
     OPENXML(@idoc, '/*') 
    WITH 
    (
     UpdatedDateTime datetime 'UpdatedDateTime' 
    ) 

运行导致以下错误：

Msg 241, Level 16, State 1, Line 12

Conversion failed when converting datetime from character string.

如何将日期时间从XML片段转换为基于SQL的日期时间？

感谢

Answer 1

尝试：

declare @stuff nvarchar (max); 

    set @stuff = 
    '<Booking xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> 
     <UpdatedDateTime>2009-08-14T15:32:09.7240556+01:00</UpdatedDateTime> 
    </Booking>'; 

    declare @iDoc int; 

    exec sp_xml_preparedocument @idoc OUTPUT, @stuff; 

    SELECT CONVERT(datetime,REPLACE(LEFT(UpdatedDateTime,23),'T',' ')),RIGHT(UpdatedDateTime,6) 
     ,CASE 
      WHEN LEFT(RIGHT(UpdatedDateTime,6),1)='+' THEN DATEADD(hh,CONVERT(int,LEFT(RIGHT(UpdatedDateTime,5),2)),CONVERT(datetime,REPLACE(LEFT(UpdatedDateTime,23),'T',' '))) 
      ELSE DATEADD(hh,-1*CONVERT(int,LEFT(RIGHT(UpdatedDateTime,5),2)),CONVERT(datetime,REPLACE(LEFT(UpdatedDateTime,23),'T',' '))) 
     END 

     FROM 
      OPENXML(@idoc, '/*') 
     WITH 
     (
      UpdatedDateTime varchar(100) 'UpdatedDateTime' 
     ) 

结果集：

----------------------- ------ ----------------------- 
2009-08-14 15:32:09.723 +01:00 2009-08-14 16:32:09.723 

(1 row(s) affected)