创建休眠标准内查询

Question

我在条件查询创建这种类型的查询休眠

SELECT * 
     FROM 
     ${hibernate.default_schema}.VW_GEMS_CUST_TRNG_RPT CUSTOMER, 
     (SELECT * FROM ${hibernate.default_schema}.VW_GEMS_VENUE WHERE ORG_NAME =?) 
     VENUE 
     WHERE 
     CUSTOMER.PRIMARY_VENUE_ROW_ID = VENUE.VENUE_ROW_ID(+) 
     AND CUSTOMER.ORG_NAME =? 
     AND CUSTOMER.CONTACT_ID =? 
     ORDER BY CUSTOMER.EVNT_START_DT DESC 

我该怎么办呢？

Answer 1

ROM子句中的子选择不能与标准API一起使用。
但是，您可以重写没有子选择的查询。

SELECT * 
FROM 
    ${hibernate.default_schema}.VW_GEMS_CUST_TRNG_RPT CUSTOMER 
inner join ${hibernate.default_schema}.VW_GEMS_VENUE VENUE 
     on (CUSTOMER.PRIMARY_VENUE_ROW_ID = VENUE.VENUE_ROW_ID(+) 
     and venue.ORG_NAME =?) 
WHERE 
     CUSTOMER.ORG_NAME =? 
     AND CUSTOMER.CONTACT_ID =? 
ORDER BY CUSTOMER.EVNT_START_DT DESC