生成内插串N次，所以我得到n个不同的答案

Question

我试图从选项列表中创建虚拟数据：

library('stringr') 
#Generate a load of strings 
line <- list(x1 = 10, x2 = 30,x3="There is no intestinal metaplasia, dysplasia or malignancy",x4="No Helicobacter are seen",x5="There is some ulceration",x6="There is no intercellular oedema in the surface epithelium",x7="PASstaining shows occasional spores, consistent with candida",x8="No herpetic viral inclusions are seen",x9="There is no dysplasia and no invasive carcinoma",x10="There is mild regenerative epithelial change, but neither dysplasia nor malignancy is seen",x11="The appearances are consistent with the endoscopic diagnosis of Barrett's oesophagus with active chronic inflammation",x12="The biopsies of oesophageal squamous mucosa show surface erosion and active chronic inflammation",x13="Numerous Candida spores and hyphae are present admixed with ulcer slough",x14="There is reactive basal cell hyperplasia and mild inflammatory epithelial atypia",x15="There is no significant increase in intraepithelialeosinophils",x16="No granulomas or viral inclusions are seen",x17="The appearances are those of Candida oesophagitis",x18="Neither dysplasia nor malignancy is seen",x19="The appearances are consistent with, but not specific for Barrett's (columnar lined) oesophagus") 
listofResults<-unlist(sample(line,2,replace=T)) 
list.of.samples <- replicate(1000, paste(sample(1:10,1), "specimens collected the largest measuring", sample(1:5,1) ,"x", sample(1:5,1) ,"x", sample(1:5,1), "mm and the smallest", sample(1:5,1) ,"x", sample(1:5,1) ,"x", sample(1:5,1), "mm"), simplify=FALSE) 

我想然后创建数据的10个样品。如果我运行：

#Merge the strings together randomly 
histop<-paste (sample(list.of.samples,1,replace=T),str_c(sample(line,sample(3:10,1),replace=T),collapse='.')) 

然后我得到随机构造的字符串就好了，正如预期的那样，每次运行它时都会发生变化。然而运行

rep(histop,10) 

只是结果相同的结果10次。所以我试图把它作为一个功能

histop<-function(){ 
    paste (sample(list.of.samples,1,replace=T),str_c(sample(line,sample(3:10,1),replace=T),collapse='.')) 
} 
rep(histop(),10) 

但我得到了同样的结果。我怎样才能得到10个不同的字符串？

Answer 1

好的我想通了。我只需要使用复制而不是代表。我需要阅读关于这个，但我认为复制实际上运行的线，而rep运行一次，然后复制结果。

replicate(20,paste (sample(list.of.samples,1,replace=T),str_c(sample(line,sample(3:10,1),replace=T),collapse='.')))