好吧,我所得到的是两种模式...如何计算满足相关模型中条件的记录?
Jiraissue:
class Jiraissue < ActiveRecord::Base
# JIRA uses a singular table name for this model
set_table_name 'jiraissue'
has_one :severity
end
严重性:
class Severity < ActiveRecord::Base
belongs_to :jiraissue
end
我想要做的就是让所有的计数Jiraissues其中jiraissue.severity =“S1”
现在事实证明,jiraissue表有一个优先列,所以我可以在模型中拉这个技巧...
Jiraissue:
class Jiraissue < ActiveRecord::Base
# JIRA uses a singular table name for this model
set_table_name 'jiraissue'
has_one :severity
def self.count_priority(priority)
where("PRIORITY = ?",priority).count()
end
end
然后在视图中做这样的事情......
<%= (1..4).map {
|priority| Jiraissue.biit.bugs.recent.count_priority(priority)
}.inspect %>
我怎样做类似的Jiraissue获得count_severity方法的东西吗?
这是行不通的(我也不会指望它)...
def self.count_severity(severity)
where("severity = ?",severity).count()
end
但我完全糊涂了。
我太完全困惑了;)...''jiraissue.severity'会返回Severity类的关联对象吗?你如何比较'jiraissue.severity =“S1”'? – nkm 2012-02-18 04:10:41