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我想从vC++ 08中的目录中检索具有.jpg扩展名的文件。我对指针不太熟悉,所以在尝试获取字符串的长度时遇到错误码。谁能帮我吗??无法获得vC++中的字符串长度
这里是我的代码..
#include<iostream>
#include <string>
#pragma warning(disable : 4996)
#include "dirent.h"
#pragma warning(default : 4996)
using namespace std;
int main(int argc, char *argv[])
{
if(argc != 2)
{
cout<<"Usage: "<<argv[0]<<" <Directory name>"<<endl;
return -1;
}
DIR *dir;
dir = opendir (argv[1]);
if (dir != NULL)
{
string name; string ext = ".jpg"; int len;
cout<<"Directory Listing for "<<argv[1]<<" : "<<endl;
struct dirent *ent;
while ((ent = readdir (dir)) != NULL)
{
name = ent->d_name;
len = name.length; // here i got error...
name = name.substr(0, len-4);
if(_stricmp(name.c_str(), ext.c_str()) == 0)
{
cout<<ent->d_name<<endl;
}
else
{
cout<<"No JPG file"<<endl;
}
}
}
else
{
cout<<"Invalid Directory name"<<endl;
return -1;
}
return 0;
}
和错误是
example.cpp(29) : error C3867: 'std::basic_string<_Elem,_Traits,_Ax>::length': function call missing argument list; use '&std::basic_string<_Elem,_Traits,_Ax>::length' to create a pointer to member
1> with
1> [
1> _Elem=char,
1> _Traits=std::char_traits<char>,
1> _Ax=std::allocator<char>
1> ]
1>\example.cpp(29) : error C2440: '=' : cannot convert from 'unsigned int (__thiscall std::basic_string<_Elem,_Traits,_Ax>::*)(void) const' to 'int'
1> with
1> [
1> _Elem=char,
1> _Traits=std::char_traits<char>,
1> _Ax=std::allocator<char>
1> ]
1> There is no context in which this conversion is possible
在此先感谢...
谢谢。这真是我的错误。这是你在深夜编码时发生的情况。 – 2012-04-02 19:39:02