2
我有多模态窗口，从其中一个我想发送几个$模型到另一个窗口它的父亲几乎没有儿子......我们不能拯救儿子，因为我们不知道父亲的id和name ..如何使控制器记住ajax发布数据Yii2
JS
$("#modal-deposit").submit(function($form) {
$form.preventDefault();
$.ajax({
type: "POST",
url: "index.php?r=family/create", // сreatedeposit создает запись.
data: $("#form-deposit").serialize(), // Сериализует the form's elements.
return false;
});
行动
public function actionCreate()
{
$family_model = new family();
$model_deposit = new FinanceIncomeExpenses();
if ($family_model->load(Yii::$app->request->post())
&& $family_model->save())
{
if ($model_deposit->sum != null)// one of the required fields
{
$model_deposit->family_id = $family_model->id;
$model_deposit->save();
}
} else {
if(Yii::$app->getRequest()->isAjax){
return $this->renderAjax('create', [
'family_model' => $family_model,
'model_deposit' => $model_deposit,
]);
}else{
return $this->render('create', [
'family_model' => $family_model,
'model_deposit' => $model_deposit,
]);
}
}
}