PHP Laravel：Ajax无法检索数据（无属性）

Question

我正在构建一个laravel应用程序，我想用ajax控制器生成一些报告。在MySQL中使用相同的原始查询，我可以看到数据，但是使用ajax我无法在我的视图页面中显示。 在控制台它显示[] No Properties

我没有得到为什么它表示对上述错误。如果有人发现有什么问题，请帮我找出答案。谢谢。

这里是我用于从数据库中检索数据的控制器：

public function ajax_view_schedule(Request $request) 
    { 

      $dept_id= $request->Input(['dept_id']); 
$schedule= DB::select(DB::raw("SELECT courses.code as c_code, courses.name as c_name,COALESCE(CONCAT('R. No',':',rooms.room_number,', ',days.name ,', ', allocate_rooms.start,' - ',allocate_rooms.end),'Not Scheduled Yet') AS schedule 
FROM departments join courses on departments.id = courses.department_id 
left join allocate_rooms on allocate_rooms.course_id=courses.id 
left join rooms on allocate_rooms.room_id=rooms.id 
left join days on allocate_rooms.day_id=days.id WHERE departments.id='.$dept_id.'")); 
     return \Response::json($schedule); 
    } 

这里与Ajax代码视图页面：

<div class="container" > 
     <h3> View Class Schedule and Room Allocation Information </h3> 

    <div class="form-group"> 
     <label for="">Department</label> 
     <select class="form-control input-sm" required id="department" name="department_id" > 
     <option>Select a Department</option> 
     @foreach($department as $row) 
     <option value="{{$row->id}}">{{$row->name}}</option> 
     @endforeach 
     </select> 
    </div> 



    <table class="table table-striped table-bordered" id="example"> 
    <thead> 
     <tr> 

     <td>Course Code</td> 
     <td>Name</td> 
     <td>Schedule Info</td>      
     </tr> 
    </thead> 
    <tbody> 

    </tbody> 
    </table>   
    </div> 

    <script type="text/javascript"> 
    $('#department').on('change',function(e){    
     var dept_id = $('#department option:selected').attr('value'); 

     $.ajaxSetup({ 
        headers: { 
         'X-CSRF-TOKEN': $('meta[name="csrf-token"]').attr('content') 
        } 
        }); 

       $.ajax({ 
        type: "POST", 
        url : "{{url('ajax-view-schedule')}}", 
        data:{dept_id:dept_id}, 
       success : function(data) { 
         var $tbody = $('#example tbody').empty();     
        $.each(data,function(index,subcatObj){      
        $tbody.append('<tr><td class="code">' + subcatObj.c_code + '</td><td class="course_name">' + subcatObj.c_name + '</td><td class="schedule">' + subcatObj.schedule + '</td></tr>'); 
         }); 
        } 
       });  
     }); 
    </script> 

Answer 1

你实际上是在双引号这样的PHP将插入你的变量

public function ajax_view_schedule(Request $request) 
    { 

      $dept_id= $request->Input(['dept_id']); 
$schedule= DB::select(DB::raw("SELECT courses.code as c_code, courses.name as c_name,COALESCE(CONCAT('R. No',':',rooms.room_number,', ',days.name ,', ', allocate_rooms.start,' - ',allocate_rooms.end),'Not Scheduled Yet') AS schedule 
FROM departments join courses on departments.id = courses.department_id 
left join allocate_rooms on allocate_rooms.course_id=courses.id 
left join rooms on allocate_rooms.room_id=rooms.id 
left join days on allocate_rooms.day_id=days.id WHERE departments.id='$dept_id'"));//remove dot from .$dept_id. 
     return \Response::json($schedule); 
    }