得到每天的多个条目只有最后一排TSQL

Question

我有一个表，是这样的：

Id  Name  EnteredOn     Percentage 
````````````````````````````````````````````````````````````` 
01  person1  2011-03-09 17:29:35.683  56.29 
02  person1  2011-03-09 17:29:35.731  76.29 
03  person1  2011-03-09 18:15:78.683  56.29 
04  person1  2011-03-10 17:29:35.683  56.29 
05  person1  2011-03-10 16:29:31.683  56.29 
06  person1  2011-03-11 17:29:35.683  56.29 

总结上面的表格，有行为天和行一天。

现在，我只想选择最新的行--单排 - 每天。
（一行9，一个用于10和一个用于11）

我不能因为时间戳的使用是不同的。我不能组和使用：

CAST(CONVERT(FLOAT, EnteredOn) AS INT) 

因为当我选择EnteredOn字段，它抱怨说，它没有分组。我不能合并distinct(cast..date...)，因为我不能得到正确的语法。

我该如何选择 - 只有姓名，输入的百分比字段与每天不同？

非常感谢提前。

Answer 1

;with cte as 
(
    select 
    *, 
    row_number() over(partition by datediff(d, 0, EnteredOn) order by EnteredOn desc) as rn 
    from YourTable 
) 
select * 
from cte 
where rn = 1 

Answer 2

1行/天：

SELECT t1.Name, t1.EnteredOn, t1.Percentage 
    FROM table t1 
    JOIN (SELECT MAX(EnteredOn) Max_EnteredOn_By_Day 
      FROM table 
     GROUP BY convert(varchar, EnteredOn, 112)) t2 
    ON t1.EnteredOn = t2.Max_EnteredOn_By_Day 

1行/人/天：

SELECT t1.Name, t1.EnteredOn, t1.Percentage 
    FROM table t1 
    JOIN (SELECT Name, MAX(EnteredOn) Max_EnteredOn_By_Day 
      FROM table 
     GROUP BY Name, convert(varchar, EnteredOn, 112)) t2 
    ON t1.Name = t2.Name 
AND t1.EnteredOn = t2.Max_EnteredOn_By_Day 

Answer 3

SELECT Name, EnteredOn, Percentage 
FROM ( SELECT *, ROW_NUMBER() OVER(PARTITION BY CONVERT(VARCHAR(8),EnteredOn,112) ORDER BY EnteredOn DESC) Corr 
     FROM YourTable) A 
WHERE Corr = 1 

Answer 4

我建议一个技巧在这里：

select top 1 with ties 
    Name, EnteredOn, Percentage 
from YourTable 
order by row_number() over(partition by datediff(d, 0, EnteredOn) order by Name, EnteredOn desc)