我有这个数据库的设计:与Hibernate迷失 - 一对多导致一个被拉回多次
CREATE TABLE report (
ID MEDIUMINT PRIMARY KEY NOT NULL AUTO_INCREMENT,
user MEDIUMINT NOT NULL,
created TIMESTAMP NOT NULL,
state INT NOT NULL,
FOREIGN KEY (user) REFERENCES user(ID) ON UPDATE CASCADE ON DELETE CASCADE
);
CREATE TABLE reportProperties (
ID MEDIUMINT NOT NULL,
k VARCHAR(128) NOT NULL,
v TEXT NOT NULL,
PRIMARY KEY(
ID, k
),
FOREIGN KEY (ID) REFERENCES report(ID) ON UPDATE CASCADE ON DELETE CASCADE
);
这Hibernate的标记:
@Table(name="report")
@Entity(name="ReportEntity")
public class ReportEntity extends Report{
@Id
@GeneratedValue(strategy = GenerationType.AUTO)
@Column(name="ID")
private Integer ID;
@Column(name="user")
private Integer user;
@Column(name="created")
private Timestamp created;
@Column(name="state")
private Integer state = ReportState.RUNNING.getLevel();
@OneToMany(mappedBy="pk.ID", fetch=FetchType.EAGER)
@JoinColumns(
@JoinColumn(name="ID", referencedColumnName="ID")
)
@MapKey(name="pk.key")
private Map<String, ReportPropertyEntity> reportProperties = new HashMap<String, ReportPropertyEntity>();
}
和
@Table(name="reportProperties")
@Entity(name="ReportPropertyEntity")
public class ReportPropertyEntity extends ReportProperty{
@Embeddable
public static class ReportPropertyEntityPk implements Serializable{
/**
* long#serialVersionUID
*/
private static final long serialVersionUID = 2545373078182672152L;
@Column(name="ID")
protected int ID;
@Column(name="k")
protected String key;
}
@EmbeddedId
protected ReportPropertyEntityPk pk = new ReportPropertyEntityPk();
@Column(name="v")
protected String value;
}
并且我在该报告的报告和4属性中插入了该字段。现在,当我执行这样的:有图有4个属性中
this.findByCriteria(
Order.asc("created"),
Restrictions.eq("user", user.getObject(UserField.ID))
)
);
我回来报告的4倍,而不仅仅是一次我不是在休眠很大,说实话,喜欢直接的SQL,但是我必须学习,但我不明白那是什么错误.....?
有什么建议吗?
它可能不是我虽然答案会是,但作品一种享受。我需要在休眠状态下快速启动,这会让我的生活变得更轻松......谢谢! – Andy 2010-05-24 18:45:57
您应该使用@ElementCollection。请参阅文档:“注意 我们建议您从@ org.hibernate.annotations.CollectionOfElements迁移到新的@ElementCollection注释。” – Dejell 2010-09-14 12:02:01