删除基于字符串的行

Question

我有一个错误日志文件，想要复制所有不匹配设置错误字符串的行。所以基本上我正在建立一个无法识别错误的单独文件。

我定义所有知道的错误类型

# Define all the error types that we need to search on 
$error_1 = "Start Date must be between 1995 and 9999" 
$error_2 = "SYSTEM.CONTACT_TYPE" 
$error_3 = "DuplicateExternalSystemIdException" 
$error_4 = "From date after To date in address" 
$error_5 = "Missing coded entry for provider type category record" 

，这是我做的读取文件

(Get-Content $path\temp_report.log) | 
    Where-Object { $_ -notmatch $error_1 } | 
    Out-File $path\uncategorised_errors.log 
(Get-Content $path\temp_report.log) | 
    Where-Object { $_ -notmatch $error_2 } | 
    Out-File $path\uncategorised_errors.log 
(Get-Content $path\temp_report.log) | 
    Where-Object { $_ -notmatch $error_3 } | 
    Out-File $path\uncategorised_errors.log 

我输入文件什么是这样的：

15 Jul 2016 20:02:11,340 ExternalSystemId cannot be the same as an existing provider 
15 Jul 2016 20:02:11,340 XXXXXXXXXXXXXXXXXXXXXXXXX 
15 Jul 2016 20:02:11,340 ZZZZZZZZZZZZZZZZZZZZZZZZ 
15 Jul 2016 20:02:11,340 DuplicateExternalSystemIdException 
15 Jul 2016 20:02:11,340 DuplicateExternalSystemIdException 
15 Jul 2016 20:02:11,340 SYSTEM.CONTACT_TYPE

和我出门的时候完全一样，我应该只有3条线：

15 Jul 2016 20:02:11,340 ExternalSystemId cannot be the same as an existing provider 
15 Jul 2016 20:02:11,340 XXXXXXXXXXXXXXXXXXXXXXXXX 
15 Jul 2016 20:02:11,340 ZZZZZZZZZZZZZZZZZZZZZZZZ

Answer 1

尝试：

(Get-Content $path\temp_report.log) | Where-Object { $_ -notmatch $error_1 -and $_ -notmatch $error_2 -and $_ -notmatch $error_3 -and $_ -notmatch $error_4 -and $_ -notmatch $error_5} | Out-File $path\uncategorised_errors.log 

Answer 2

充分利用已知错误的阵列，完全使用Select-String

$errors=@(
    "Start Date must be between 1995 and 9999", 
    "SYSTEM.CONTACT_TYPE", 
    "DuplicateExternalSystemIdException", 
    "From date after To date in address", 
    "Missing coded entry for provider type category record" 
) 

Select-String -Path D:\log.txt -NotMatch -Pattern $errors