经过对此的进一步思考,我意识到我可以通过两遍。这就是我最终的结果。欢迎对此方法发表评论:
var table = new byte[60, 10000];
for(int i = 0; i < 60; i++)
{
// we want at least half the row to be blank
int j = 0;
while(j < 10000)
{
var width = rand.Next(7, 200);
j += width * 2;
var vol = (byte)rand.Next(50, 125);
for(int k = j - width; k < Math.Min(10000, j); k++)
table[i, k] = vol;
}
}
var midiEvents = new List<BASS_MIDI_EVENT>();
midiEvents.Add(new BASS_MIDI_EVENT(BASSMIDIEvent.MIDI_EVENT_PROGRAM, 0, 0, 0, 0));
for(int j = 0; j < 10000; j++)
{
for(int i = 0; i < 60; i++)
{
var cur = (int)table[i, j];
var left = j > 0 ? table[i, j - 1] : 0;
if(cur > 0 && left == 0)
{
cur <<= 8;
cur |= i + 33;
midiEvents.Add(new BASS_MIDI_EVENT(BASSMIDIEvent.MIDI_EVENT_NOTE, cur, 0, j, 0));
}
else if(cur == 0 && left > 0)
{
midiEvents.Add(new BASS_MIDI_EVENT(BASSMIDIEvent.MIDI_EVENT_NOTE, i + 33, 0, j, 0));
}
}
}