2013-02-11 59 views
3

我有一个函数,使用正则表达式返回给定url的根域。Javascript简单的正则表达式来寻找根域

http://jsfiddle.net/hSpsT/

function cleanUp(url) { 
    url = url.replace(new RegExp(/^\s+/),""); // START 
    url = url.replace(new RegExp(/\s+$/),""); // END 

    // IF FOUND, CONVERT BACK SLASHES TO FORWARD SLASHES 
    url = url.replace(new RegExp(/\\/g),"/"); 

    // IF THERE, REMOVES 'http://', 'https://' or 'ftp://' FROM THE START 
    url = url.replace(new RegExp(/^http\:\/\/|^https\:\/\/|^ftp\:\/\//i),""); 

    // IF THERE, REMOVES 'www.' FROM THE START OF THE STRING 
    url = url.replace(new RegExp(/^www\./i),""); 
    //remove slash from end 
    url = url.replace(new RegExp(/\/$/i),"");  
    return url; 
} 

,但它使用正则表达式的多,我们所担心的性能。是否有更好的方法来做同样的一行正则表达式?

注意:

document.location.host似乎不工作在我的情况。

回答

5

Extract hostname name from string

尝试:

function cleanUp(url) { 
    var url = $.trim(url); 
    if(url.search(/^https?\:\/\//) != -1) 
     url = url.match(/^https?\:\/\/([^\/?#]+)(?:[\/?#]|$)/i, ""); 
    else 
     url = url.match(/^([^\/?#]+)(?:[\/?#]|$)/i, ""); 
    return url[1]; 
} 

alert(cleanUp(' http://www.google.com/about.html')); 
alert(cleanUp(' www.google.com/about.html')); 
+0

谢谢,看起来不错,我会彻底测试并回复。 – Selvam 2013-02-11 11:14:48

+0

我已将它更新为www.google.com,http://jsfiddle.net/svjTC/1/,在这种情况下可能会失败,我们可以扩展它吗? – Selvam 2013-02-12 05:07:16

+1

@Selvam试试这个:http://jsfiddle.net/mwHHH/ – geniuscarrier 2013-02-12 19:16:53

1

试试这个:

http://jsfiddle.net/picklespy/gb34u/1/

它适用于所有现代浏览器,甚至在IE 5.5+。

var url = document.createElement('a'); 
url.href = 'http://maps.test.google.com'; 
var host = url.hostname; 

host = host.split('.'); 

var domain = host.pop(); 
domain = host.pop() + '.' + domain; 

alert('Root is: ' + domain) 
+2

谢谢,但可能会失败 'http://google.co.in'? – Selvam 2013-02-11 11:13:08