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我目前正在尝试构建一个程序,该程序读取文件,扫描该文件,并输出包含“标记”的文件中的所有单词。我当前难住并希望获得!一些帮助无限循环和获取不正确的输出
#include <iostream>
// For file I/O:
#include <fstream>
#include <cstdlib>
#include <iomanip>
using namespace std;
// Prototype the count function so we can have it below it's first
// use in main().
void count(istream& in, int& lines, int& words, int& characters);
/*
* wc <filename>
*/
int main(int argc, char *argv[])
{
if (argc < 2) {
cerr << "Usage: wc <filename>" << endl;
return 0;
}
// Open the file specified by argv[1] for reading:
// Constructs a ifstream object called "in":
ifstream in(argv[1]);
// Was there a problem opening the file?
if (!in.good()) {
cerr << "Unable to open file [" << argv[1] << "] for reading." << endl;
return 1;
}
int lines = 0, words = 0, characters = 0;
count(in, lines, words, characters);
cout << setw(5) << lines << " " << words << " " <<
characters << " " << argv[1] << endl;
// Close the input stream:
in.close();
}
void count(istream& in, int& lines, int& words, int& characters)
{
int i;
char s;
int ch;
bool inword = false;
// Read until the end of file is reached, or there was an error:
while (!in.eof()) {
// Read a character from the input stream "in":
s = in.get(); //Set char s = in.get
for(i=0; s != 0; i++){ //Loop to iterate through the characters
while(s == '"'){ //While s is equal "
cout << s << endl; // Print s
if(s == '"') // If we hit another ", then we break
break;
}
}
if (in.good() == false) return;
characters++;
if (!isspace(ch) && !inword) {
inword = true;
words++;
} else if (isspace(ch) && inword) {
inword = false;
}
if (ch == '\n') lines++;
}
}
我做到了,但我似乎仍然无限循环,它也没有打印任何东西,它似乎只是cout结束。 – Frebadyia
忽略最后的评论,我想出了为什么它无限循环。我现在正在陷入seg故障..对此有何评论? – Frebadyia
也许使用gdb? – Karthik