c＃中的.rdlc报告不显示任何输出数据？

Question

我的朋友即时通讯使用Visual Studio 2008，并且我在c＃中开发了一个小型项目，现在我想在其中添加报告（.rdc reports）。这里是我的代码

try 
     { 
      reportViewer1.Reset(); 
      con.Open(); 
      command.Connection = con; 
      command.CommandType = CommandType.StoredProcedure; 
      command.CommandText = "select_book_specific"; 

      param = new SqlParameter("@isbn", "isbn1"); 
      param.Direction = ParameterDirection.Input; 
      param.DbType = DbType.String; 
      command.Parameters.Add(param); 

      adapter = new SqlDataAdapter(command); 
      adapter.Fill(ds); 


     // for (int i = 0; i <= ds.Tables[0].Columns.Count - 1; i++) 
      // { 

      // MessageBox.Show(ds.Tables[0].Rows[0][i].ToString()); 

      //} For testing purpose 

      this.reportViewer1.LocalReport.ReportPath = @"C:\Documents and Settings\Administrator\My Documents\Visual Studio 2008\Projects\WindowsFormsApplication1\WindowsFormsApplication1\Report1.rdlc"; 


this.reportViewer1.LocalReport.DataSources.Add(newReportDataSource("Books",ds.Tables[0].TableName.ToString())); 
this.reportViewer1.RefreshReport(); 


} 
catch(exception ex){messageBox.show(ex.message);} 

Answer 1

尝试

try 
{ 
    reportViewer1.Reset(); 
    con.Open(); 
    command.Connection = con; 
    command.CommandType = CommandType.StoredProcedure; 
    command.CommandText = "select_book_specific"; 

    param = new SqlParameter("@isbn", "isbn1"); 
    param.Direction = ParameterDirection.Input; 
    param.DbType = DbType.String; 
    command.Parameters.Add(param); 

    adapter = new SqlDataAdapter(command); 
    adapter.Fill(ds); 
    this.reportViewer1.LocalReport.ReportPath = @"C:\Documents and Settings\Administrator\My Documents\Visual Studio 2008\Projects\WindowsFormsApplication1\WindowsFormsApplication1\Report1.rdlc"; 
    this.reportViewer1.LocalReport.DataSources.Clear(); 
    this.reportViewer1.LocalReport.DataSources.Add(new ReportDataSource(ds.DataSetName + "_" + ds.TableName, ds.Tables[0])); 
    this.reportViewer1.LocalReport.Refresh(); 
}catch(Exception ex) 
{ 
    messageBox.show(ex.message); 
}