2
我在这里有一个小问题。所以,我正在撰写一些关于众所周知的REST API的调用。一切都进展顺利,除了我希望所有响应都以列表形式显示(这对我来说更好)。我的功能是这样的:Python:显示为列表问题httplib.HTTPMessage
import sys, httplib
HOST = "api.sugarsync.com"
API_URL = "https://api.sugarsync.com"
def do_request(xml_location):
request = open(xml_location,"r").read()
webservice = httplib.HTTPS(HOST)
webservice.putrequest("POST", "authorization", API_URL)
webservice.putheader("Host", HOST)
webservice.putheader("User-Agent","Python post")
webservice.putheader("Content-type", "application/xml")
webservice.putheader("Content-type", "application/xml")
webservice.putheader("Accept", "*/*")
webservice.putheader("Content-length", "%d" % len(request))
webservice.endheaders()
webservice.send(request)
statuscode, statusmessage, header = webservice.getreply()
result = webservice.getfile().read()
return statuscode, statusmessage, header
return result
do_request('C://Users/my_user/Documents/auth.xml')
我习惯了,用split(),但在这种情况下,结果是这样的:
[201, 'Created', <httplib.HTTPMessage instance at 0x0000000001F68AC8>]
嗯,我还需要第三个对象(例如httplib.HTTPMessage在0x0000000001F68AC8>)被显示为列表,以提取其中的一些数据。
在此先感谢!