怎么算选择具有3列不同的MySQL

Question

我的表像：

ID_USER USERNAME_USER REF_USER STATUS_AKTIF 
1  a      aktif 
2  b    a  tidak 
3  c    a  aktif 
4  d    b  aktif 
5  e    a  aktif 

，我使用此代码：

select REF_USER, count(distinct USERNAME_USER) as TOTAL from TABLE where (REF_USER IS NOT NULL AND REF_USER!="" AND STATUS_AKTIF='aktif') group by REF_USER 

，但我只得到：

REF_USER TOTAL 
a  2 
b  1 

我该如何删除b？因为用户B STATUS_AKTIF是tidak

Answer 1

只需通过

SELECT count(*) as total, username_user FROM table 
WHERE (REF_USER IS NOT NULL AND REF_USER!="" AND STATUS_AKTIF='aktif') 
GROUP BY username_user