我有以下的JSON文件:bash脚本过滤JSON文本
{
"error": 0,
"data": {
"0": {
"orderid": "40007600",
"price": "9.99",
"listingname": "iPhone 8",
"smallphoto": "https://images-eu.ssl-images-amazon.com/images/I/51b5iaLTjgL._SL160_.jpg",
"photo": "https://images-eu.ssl-images-amazon.com/images/I/51b5iaLTjgL.jpg"
},
"1": {
"orderid": "40007598",
"price": "9.99",
"listingname": "iPhone 8 Plus",
"smallphoto": "https://images-eu.ssl-images-amazon.com/images/I/51CVLqsSNkL._SL160_.jpg",
"photo": "https://images-eu.ssl-images-amazon.com/images/I/51CVLqsSNkL.jpg"
},
"4": {
"orderid": "40007595",
"price": "9.39",
"listingname": "Nadelflaschen",
"smallphoto": "https://images-eu.ssl-images-amazon.com/images/I/41OHDP2rAeL._SL160_.jpg",
"photo": "https://images-eu.ssl-images-amazon.com/images/I/41OHDP2rAeL.jpg"
},
}
}
我如何可以筛选出bash脚本的一切,所以我得到“smallphoto”的所有图像的URL到一个文本文件?
f.e.来自“Nadelflaschen”的https://images-eu.ssl-images-amazon.com/images/I/41OHDP2rAeL.SL160.jpg
我尝试了awk和jq命令。但我只是为了理解jq语法而倾倒。
awk是可能的,但我只得到与反斜杠的未过滤链接,这是行不通的。
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