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这是我非常关心的第一个话题。 我仍在学习如何验证，但我真的需要你的帮助。简单验证PHP
我需要验证名字，姓氏，街道，郊区，邮编，电子邮件，身份和出生日期。
如果我这样做是这样的：
if (empty($firstname)) {$errors[] =" First Name Can not be Empty <br> ";}
if (empty($lastname)) {$errors[] =" Last Name Can not be Empty <br> ";}
if (empty($street)) {$errors[] =" Street Can not be Empty <br> ";}
if (empty($suburb)) {$errors[] =" Suburb Can not be Empty <br> ";}
if (empty($postcode)) {$errors[] =" Postcode Can not be Empty <br> ";}
// elseif (!is_numeric($postcode)) {$errors[] =" Postcode must be numeric ";}
elseif(!preg_match("/\^\(\[0\-9\]\{5\}\(\[\-\\s\]\?\[0\-9\]\{4\}\)\?\)\$/", $postcode)) {$errors[] =" Please enter a valid post number <br> ";}
if(!preg_match("/^[_a-z0-9-]+(.[_a-z0-9-]+)*@[a-z0-9-]+(.[a-z0-9-]+)*(.[a-z]{2,3})$/i", $myemail)) {$errors[] =" You have entered and invalid email address <br> ";}
if (empty($DOB)) {$errors[] =" Date only <br> ";}
它给了我错误的堆。
这是我的全部的PHP代码：
<?php
function renderForm($first, $last, $st, $sub, $pcode, $em, $sta, $dofb, $error)
{
?>
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN" "http://www.w3.org/TR/html4/strict.dtd">
<html>
<head>
<title>Add Student</title>
</head>
<body>
<?php
if ($error != '')
{
echo '<div style="padding:4px; border:1px solid red; color:red;">'.$error.'</div>';
}
echo "<p><b>Add new student details</b></p>";
?>
<form action="" method="post">
<div>
<strong>First name: </strong> <input type="text" name="FNAME" value="<?php echo $first; ?>" /><br/>
<strong>Last name: </strong> <input type="text" name="LNAME" value="<?php echo $last; ?>" /><br/>
<strong>Street: </strong> <input type="text" name="STREET" value="<?php echo $st; ?>" /><br/>
<strong>Suburb: </strong> <input type="text" name="SUBURB" value="<?php echo $sub; ?>" /><br/>
<strong>Postcode: </strong> <input type="text" name="POSTCODE" value="<?php echo $pcode; ?>" /><br/>
<strong>Email: </strong> <input type="text" name="EMAIL" value="<?php echo $em; ?>" /><br/>
<strong>Status: </strong> <input type="text" name="STATUS" value="<?php echo $sta; ?>" /><br/>
<strong>Date of Birth: </strong> <input type="text" name="DOB" value="<?php echo $dofb; ?>" /><br/>
<p>Required Field</p>
<input type="submit" name="submit" value="Submit">
</div>
</form>
<p><a href="view.php">Update & delete students</a></p>
</body>
</html>
<?php
}
include('dbconnect.php');
if (isset($_POST['submit']))
{
$firstname = mysql_real_escape_string(htmlspecialchars($_POST['FNAME']));
$lastname = mysql_real_escape_string(htmlspecialchars($_POST['LNAME']));
$street = mysql_real_escape_string(htmlspecialchars($_POST['STREET']));
$suburb = mysql_real_escape_string(htmlspecialchars($_POST['SUBURB']));
$postcode = mysql_real_escape_string(htmlspecialchars($_POST['POSTCODE']));
$email = mysql_real_escape_string(htmlspecialchars($_POST['EMAIL']));
$status = mysql_real_escape_string(htmlspecialchars($_POST['STATUS']));
$dob = mysql_real_escape_string(htmlspecialchars($_POST['DOB']));
if ($firstname == '' || $lastname == '' || $street == '' || $suburb == '' || $postcode == '' || $email == '' || $status == '' || $dob == '')
{
$error = 'Your field is empty';
renderForm($firstname, $lastname, $street, $suburb, $postcode, $email, $status, $dob, $error);
}
else
{
mysql_query("INSERT student SET FNAME='$firstname', LNAME='$lastname', STREET='$street', SUBURB='$suburb', POSTCODE='$postcode', EMAIL='$email', STATUS='$status', DOB='$dob' ")
or die(mysql_error());
header("Location: view.php");
}
}
else
{
renderForm('','','','','','','','','');
}
?>
我不知道该怎么做，我真的很困惑，所以我在想，如果你能帮助我吗？是的，我到处搜索，并按照一些教程甚至在这个网站上的答案，但它不起作用。我还在挣扎。 您的帮助将不胜感激！ 谢谢。
编辑：链接：http://viper-7.com/HfyXw3 链接DBCONNECT：http://viper-7.com/14PG1H
“它给了我大量的错误” - 什么错误？ – Quentin 2014-10-06 08:41:54
你在哪里定义了这个函数“renderForm” – alagu 2014-10-06 08:44:31
好吧现在没有错误。最后！但是，当我输入所有表单时，错误消息仍然显示“您的字段为空”？ – imn00b 2014-10-06 08:49:12