在C++中，如何结合搜索功能和开关，所以开关可以要求用户从搜索结果中选择并显示结果信息？

Question

1. 该代码要求用户从团队中挑选一名玩家，并显示该玩家的统计数据。搜索必须能够进行部分输入搜索。这是我迄今为止提出的代码。但是我被卡在交换机工作正常或搜索功能之间，但不能使它们一起工作。谢谢您的帮助。

   #include <iostream> 
   #include <string> 
   #include <fstream> 
   
   using namespace std; 
   
   int main() 
   { 
   int index = 0; 
   int choice; 
   int counter = 1; 
   string player, result; 
   
   
   cout << "\n\nThis program will ask the user for a player name from\n"; 
   cout << "the team Dallas Mavericks and give the statistics of the player.\n"; 
   cout << " *Last Name First\n"; 
   cout << " *Seperated By Comma\n"; 
   cout << " *Use correct capitalization\n"; 
   cout << "Please enter player's name: "; 
   getline(cin, player); 
   
   ifstream inputFile; 
   inputFile.open("statisticsMavs.txt"); 
   if (inputFile.fail()) 
   { 
       cout << "Could not open file"; 
       return 1; 
   } 
   
   ofstream outputFile; 
   outputFile.open("playerStats.txt"); 
   
   if (outputFile.fail()) 
   { 
       cout << "Could not open file"; 
       return 1; 
   } 
   
   for (index = 0; getline(inputFile, result); index++) 
   { 
       if (result.find(player) != string::npos) 
       { 
        cout << endl << counter++ << " " << result.substr(0, 20) << endl; 
        continue; 
       } 
   
       else 
       { 
        continue; 
        cout << "Could not find player! Please enter another name: "; 
        getline(cin, player); 
       } 
   } 
   
   
   cout << "Please choose the number from the correct search result: "; 
   cin >> choice; 
   switch (choice) 
   { 
   case 1: outputFile << result << endl; 
       return 1; 
   case 2: outputFile << result << endl; 
       return 1; 
   case 3: outputFile << result << endl; 
       return 1; 
   case 4: outputFile << result << endl; 
       return 1; 
   default: cout << choice << " is not a valid input" << endl; 
   } 
   
   
   inputFile.close(); 
   outputFile.close(); 
   
   
   
   } 
   

Answer 1

我相信下面，而不是使用开关，并得到完成你所期望，即发现多达4分匹配的结果，然后给一个选择的人。由于我没有这些文本文件，我不确定它是如何工作的，但它编译，看起来应该是这样。我试图简化在那里我可以，在保持原意（但我认为这里原来是关闭的是，结果举行的最后一次读取匹配的字符串，所以没有办法选择一个较早的一个。

#include <iostream> 
#include <string> 
#include <fstream> 

using namespace std; 
int main() 
{ 
int choice; 
int counter = 0; 
string player, result; 
string results[4]; 


cout << "\n\nThis program will ask the user for a player name from\n"; 
cout << "the team Dallas Mavericks and give the statistics of the player.\n"; 
cout << " *Last Name First\n"; 
cout << " *Seperated By Comma\n"; 
cout << " *Use correct capitalization\n"; 
cout << "Please enter player's name: "; 
getline(cin, player); 

ifstream inputFile; 
inputFile.open("statisticsMavs.txt"); 
if (inputFile.fail()) 
{ 
    cout << "Could not open file"; 
    return 1; 
} 

ofstream outputFile; 
outputFile.open("playerStats.txt"); 

if (outputFile.fail()) 
{ 
    cout << "Could not open file"; 
    inputFile.close(); 
    return 1; 
} 

while ((counter<4) && getline(inputFile, result)) 
{ 
    if (result.find(player) != string::npos) 
    { 
     results[counter++]=result; 
     cout << endl << counter << " " << result.substr(0, 20) << endl; 

    } 


} 
if (counter == 0) 
    { 
     cout << "Could not find player! Terminating."<<endl; 
    } 
else 
{ 
cout << "Please choose the number from the correct search result: "; 
cin >> choice; 

if ((choice>=1) && (choice<=counter)) 
{ 
    outputFile << results[choice-1] << endl; 
    inputFile.close(); 
    outputFile.close(); 
    return 1; 
} 
else 
{ 
cout << choice << " is not a valid input" << endl; 
} 
} 

inputFile.close(); 
outputFile.close(); 



}