一个web.xml中有多个球衣servlets

Question

是否可以在一个web.xml中包含多个球衣servlets？我试图用这种方式做RESTfull版本控制：

<?xml version="1.0" encoding="UTF-8"?> 
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" id="WebApp_ID" version="2.5"> 

    <display-name>myapi</display-name> 

    <context-param> 
    <param-name>contextConfigLocation</param-name> 
    <param-value>/WEB-INF/context-v1.xml /WEB-INF/context-v2.xml</param-value> 
    </context-param> 

    <listener> 
    <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class> 
    </listener> 

    <servlet> 
    <servlet-name>REST-V1</servlet-name> 
    <servlet-class>com.sun.jersey.spi.spring.container.servlet.SpringServlet</servlet-class> 
    <init-param> 
     <param-name>com.sun.jersey.config.property.packages</param-name> 
     <param-value>com.myapi.rest.v1</param-value> 
    </init-param> 
    <load-on-startup>1</load-on-startup> 
    </servlet> 

    <servlet-mapping> 
    <servlet-name>REST-V1</servlet-name> 
    <url-pattern>/v1/*</url-pattern> 
    </servlet-mapping> 

    <servlet> 
    <servlet-name>REST-V2</servlet-name> 
    <servlet-class>com.sun.jersey.spi.spring.container.servlet.SpringServlet</servlet-class> 
    <init-param> 
     <param-name>com.sun.jersey.config.property.packages</param-name> 
     <param-value>com.myapi.rest.v2</param-value> 
    </init-param> 
    <load-on-startup>2</load-on-startup> 
    </servlet> 

    <servlet-mapping> 
    <servlet-name>REST-V2</servlet-name> 
    <url-pattern>/v2/*</url-pattern> 
    </servlet-mapping> 

    <welcome-file-list> 
    <welcome-file>index.html</welcome-file> 
    </welcome-file-list> 

</web-app> 

但是，spring context-v1和context-v2应该分开加载吗？因为他们有豆类，它们具有相同的名称等

编辑：

如果你在我的控制台输出它加载的资源（管理/ INFO）两次，每次servlet的样子：

15.07.2012 14:47:08 com.sun.jersey.api.core.PackagesResourceConfig init 
INFO: Scanning for root resource and provider classes in the packages: 
    com.myapi.rest.v1 
15.07.2012 14:47:08 com.sun.jersey.api.core.ScanningResourceConfig logClasses 
INFO: Root resource classes found: 
    class com.myapi.rest.v1.LOAdminResource 
    class com.myapi.rest.v1.LOInfoResource 
15.07.2012 14:47:08 com.sun.jersey.api.core.ScanningResourceConfig init 
INFO: No provider classes found. 
15.07.2012 14:47:09 com.sun.jersey.spi.spring.container.servlet.SpringServlet getContext 
INFO: Using default applicationContext 
15.07.2012 14:47:09 com.sun.jersey.spi.spring.container.SpringComponentProviderFactory registerSpringBeans 
INFO: Registering Spring bean, adminResource_v2, of type com.myapi.rest.v2.LOAdminResource as a root resource class 
15.07.2012 14:47:09 com.sun.jersey.spi.spring.container.SpringComponentProviderFactory registerSpringBeans 
INFO: Registering Spring bean, infoResource_v2, of type com.myapi.rest.v2.LOInfoResource as a root resource class 
15.07.2012 14:47:09 com.sun.jersey.spi.spring.container.SpringComponentProviderFactory registerSpringBeans 
INFO: Registering Spring bean, adminResource_v1, of type com.myapi.rest.v1.LOAdminResource as a root resource class 
15.07.2012 14:47:09 com.sun.jersey.spi.spring.container.SpringComponentProviderFactory registerSpringBeans 
INFO: Registering Spring bean, infoResource_v1, of type com.myapi.rest.v1.LOInfoResource as a root resource class 
15.07.2012 14:47:09 com.sun.jersey.server.impl.application.WebApplicationImpl _initiate 
INFO: Initiating Jersey application, version 'Jersey: 1.8 06/24/2011 12:17 PM' 
15.07.2012 14:47:09 com.sun.jersey.api.core.PackagesResourceConfig init 
INFO: Scanning for root resource and provider classes in the packages: 
    com.myapi.rest.v2 
15.07.2012 14:47:09 com.sun.jersey.api.core.ScanningResourceConfig logClasses 
INFO: Root resource classes found: 
    class com.myapi.rest.v2.LOAdminResource 
    class com.myapi.rest.v2.LOInfoResource 
15.07.2012 14:47:09 com.sun.jersey.api.core.ScanningResourceConfig init 
INFO: No provider classes found. 
15.07.2012 14:47:09 com.sun.jersey.spi.spring.container.servlet.SpringServlet getContext 
INFO: Using default applicationContext 
15.07.2012 14:47:09 com.sun.jersey.spi.spring.container.SpringComponentProviderFactory registerSpringBeans 
INFO: Registering Spring bean, adminResource_v2, of type com.myapi.rest.v2.LOAdminResource as a root resource class 
15.07.2012 14:47:09 com.sun.jersey.spi.spring.container.SpringComponentProviderFactory registerSpringBeans 
INFO: Registering Spring bean, infoResource_v2, of type com.myapi.rest.v2.LOInfoResource as a root resource class 
15.07.2012 14:47:09 com.sun.jersey.spi.spring.container.SpringComponentProviderFactory registerSpringBeans 
INFO: Registering Spring bean, adminResource_v1, of type com.myapi.rest.v1.LOAdminResource as a root resource class 
15.07.2012 14:47:09 com.sun.jersey.spi.spring.container.SpringComponentProviderFactory registerSpringBeans 
INFO: Registering Spring bean, infoResource_v1, of type com.myapi.rest.v1.LOInfoResource as a root resource class 
15.07.2012 14:47:09 com.sun.jersey.server.impl.application.WebApplicationImpl _initiate 
INFO: Initiating Jersey application, version 'Jersey: 1.8 06/24/2011 12:17 PM' 

Answer 1

是的，您可以在web.xml中指定两个或多个servlet。请记住为每一个指定一个不同的servlet映射。

<servlet> 
    <servlet-name>servletOne</servlet-name> 
    <servlet-class>com.sun.jersey.spi.spring.container.servlet.SpringServlet</servlet-class> 
    <init-param> 
    <param-name>com.sun.jersey.config.property.packages</param-name> 
    <param-value>com.packageOne</param-value> 
    </init-param> 
    <load-on-startup>1</load-on-startup> 
</servlet> 
<servlet> 
    <servlet-name>servletTwo</servlet-name> 
    <servlet-class>com.sun.jersey.spi.spring.container.servlet.SpringServlet</servlet-class> 
    <init-param> 
    <param-name>com.sun.jersey.config.property.packages</param-name> 
    <param-value>com.packageTwo</param-value> 
    </init-param> 
    <load-on-startup>2</load-on-startup> 
</servlet> 

<servlet-mapping> 
    <servlet-name>ServletOne</servlet-name> 
    <url-pattern>/v1/*</url-pattern> 
</servlet-mapping> 
    <servlet-mapping> 
    <servlet-name>ServletTwo</servlet-name> 
<url-pattern>/v2/*</url-pattern> 
</servlet-mapping> 

的initParameter loadOnStartup定义（在这种情况下，第一servletOne然后servletTwo），在该小服务程序被加载的顺序。

Answer 2

的事情是，当你使用新泽西州和春天一起，泽西/春天的servlet经过所有可用的Spring bean和一切资源和提供者类，将其中找到注册。

如果您在使用相同（根）范围内的多个州/春servlet和这样就共享bean定义，则该过程对于每一个这样的servlet和资源提供者类进行注册几次。

为了避免相同的bean的多重注册，在相应的Jesrey /弹簧的servlet的子上下文定义这种豆。

它甚至没有必要，除非是必需的Spring管理和泽西管理类的混合物在web.xml中声明类提供初始化参数。

<context-param> 
    <param-name>contextConfigLocation</param-name> 
    <param-value>/WEB-INF/root-context.xml</param-value> 
</context-param> 

... 

<servlet> 
    <servlet-name>REST-V1</servlet-name> 
    <servlet-class>com.sun.jersey.spi.spring.container.servlet.SpringServlet</servlet-class> 
    <init-param> 
     <param-name>contextConfigLocation</param-name> 
     <param-value>/WEB-INF/context-v1.xml</param-value> 
    </init-param> 
    <load-on-startup>1</load-on-startup> 
</servlet> 

<servlet> 
    <servlet-name>REST-V2</servlet-name> 
    <servlet-class>com.sun.jersey.spi.spring.container.servlet.SpringServlet</servlet-class> 
    <init-param> 
     <param-name>contextConfigLocation</param-name> 
     <param-value>/WEB-INF/context-v1.xml /WEB-INF/context-v2.xml</param-value> 
    </init-param> 
    <load-on-startup>2</load-on-startup> 
</servlet> 

... 

Answer 3

我知道这个话题是老的回答。但我的回答可以帮助其他人。

我们可以在web.xml配置多个资源封装，这些分隔符：

1. 空白
2. 逗号（，）
3. 分号（;）
4. Nextline

实施例：

<?xml version="1.0" encoding="UTF-8"?> 
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" id="WebApp_ID" version="3.0"> 
    <display-name>MultiplePackageRest</display-name> 
    <servlet> 
    <servlet-name>JerseyMultiplePackage</servlet-name> 
    <servlet-class>org.glassfish.jersey.servlet.ServletContainer</servlet-class> 
    <init-param> 
     <param-name>jersey.config.server.provider.packages</param-name> 
     <param-value>info.javadoff.rest1,info.javadoff.rest2,...</param-value> 
    </init-param> 
     <load-on-startup>1</load-on-startup> 
    </servlet> 
    <servlet-mapping> 
    <servlet-name>JerseyMultiplePackage</servlet-name> 
    <url-pattern>/api/*</url-pattern> 
    </servlet-mapping> 
</web-app> 

Answer 4

还有一个可能性是在com.sun.jersey.spi.spring.container.servlet.SpringServlet覆盖的一种方法。启动方法看起来像这样（版本1.19。1）：

@Override 
protected void initiate(ResourceConfig rc, WebApplication wa) { 
    try { 
     SpringComponentProviderFactory springComponentProviderFactory = new SpringComponentProviderFactory(rc, getContext()); 
     rc.getClasses().removeIf(clazz -> clazz.getPackage().getName().startsWith("bla")); 
     wa.initiate(rc, springComponentProviderFactory); 
    } catch (RuntimeException e) { 
     LOGGER.log(Level.SEVERE, "Exception occurred when intialization", e); 
     throw e; 
    } 
} 

了一下：

@Override 
protected void initiate(ResourceConfig rc, WebApplication wa) { 
    try { 
     wa.initiate(rc, new SpringComponentProviderFactory(rc, getContext())); 
    } catch (RuntimeException e) { 
     LOGGER.log(Level.SEVERE, "Exception occurred when intialization", e); 
     throw e; 
    } 
} 

如果你在这样的子类更改代码，那么你可以根据你的条件（例如包名）过滤掉不需要的春天豆哈克解决方案，但完美的作品。