通过php代码上传文件到数据库

-2

我已经提出了一个应用程序来上传文件，它的工作良好。现在我想将我的文件上传到数据库，并且我还想通过访问数据库在列表中显示上传的文件名。通过php代码上传文件到数据库

所以请帮我做这个。我的代码是下面给出：

function uploadFile() { 
    global $template; 
    //$this->UM_index = $this->session->getUserId(); 
    switch($_REQUEST['cmd']){ 


     case 'upload': 


      $filename = array(); 
      //set upload directory 
      //$target_path = "F:" . '/uploaded/'; 
      for($i=0;$i<count($_FILES['ad']['name']);$i++){ 
      if($_FILES["ad"]["name"]) 
      { 
       $filename = $_FILES["ad"]["name"][$i]; 
       $source = $_FILES["ad"]["tmp_name"][$i]; 
       $type = $_FILES["ad"]["type"]; 

       $name = explode(".", $filename); 
       $accepted_types = array('text/html','application/zip', 'application/x-zip-compressed', 'multipart/x-zip', 'application/x-compressed'); 
       foreach($accepted_types as $mime_type) 
       { 
        if($mime_type == $type) 
        { 
         $okay = true; 
         break; 
        } 
       } 

       $continue = strtolower($name[1]) == 'zip' ? true : false; 
       if(!$continue) { 
       $message = "The file you are trying to upload is not a .zip file. Please try again."; 
       } 
       $target_path = "F:" . '/uploaded/'.$filename; 
       // change this to the correct site path 
       if(move_uploaded_file($source, $target_path)) { 
       $zip = new ZipArchive(); 
       $x = $zip->open($target_path); 
       if ($x === true) { 
       $zip->extractTo("F:" . '/uploaded/'); // change this to the correct site path 
       $zip->close(); 

       unlink($target_path); 
       } 
       $message = "Your .zip file was uploaded and unpacked."; 
       } else {  
       $message = "There was a problem with the upload. Please try again."; 
       } 

      } 
     } 
      echo "Your .zip file was uploaded and unpacked."; 
      $template->main_content = $template->fetch(TEMPLATE_DIR . 'donna1.html'); 
      break; 
     default: 
      $template->main_content = $template->fetch(TEMPLATE_DIR . 'donna1.html'); 
      //$this->assign_values('cmd','uploads'); 
      $this->assign_values('cmd','upload'); 
} 
}

我的HTML页面

<html> 
    <link href="css/style.css" rel="stylesheet" type="text/css"> 
     <!--<form action="{$path_site}{$index_file}" method="post" enctype="multipart/form-data">--> 
<form action="index.php?menu=upload_file&cmd=upload" method="post" enctype="multipart/form-data"> 

<div id="main"> 
    <div id="login"> 

      <br /> 
      <br /> 

      Ad No 1: 
       <input type="file" name="ad[]" id="ad1" size="10" />&nbsp;&nbsp;Image(.zip)<input type="file" name="ad[]" id="ad1" size="10" /> Sponsor By : <input type="text" name="ad3" id="ad1" size="25" /> 
       <br /> 
       <br /> 

    </div> 
</div> 
</form> 
    </html>

来源

2011-01-05 ruhit

你的问题是什么？ – 2011-01-05 12:44:12

你会好心为我写我的应用程序。谢谢。 – dqhendricks 2011-01-05 22:36:05