在oracle中生成IP地址

我有一个数据库，其中一个字段具有IP地址的值。默认值是12.123.60.165。从这些默认值我必须生成IP地址。最大值将是256.256.256.256。在oracle中生成IP地址

这是我的功能，仍然不能掩盖我需要

/* Formatted on 9/26/2017 9:44:51 AM (QP5 v5.115.810.9015) */ 
SET SERVEROUTPUT ON 

DECLARE 
    IP INTEGER; 
    IP1 INTEGER; 
    IP2 INTEGER; 
    IP3 INTEGER; 
    IP4 INTEGER; 
    IPI INTEGER := 1; 
BEGIN 

    IP1 := FLOOR (IPI/POWER (2, 24)); 
    IPI := IPI - (IP1 * POWER (2, 24)); 
    IP2 := FLOOR (IPI/POWER (2, 16)); 
    IPI := IPI - (IP2 * POWER (2, 16)); 
    IP3 := FLOOR (IPI/POWER (2, 8)); 
    IPI := IPI - (IP3 * POWER (2, 8)); 
    IP4 := IPI; 

    DBMS_OUTPUT.PUT_LINE (IP1 || '.' || IP2 || '.' || IP3 || '.' || IP4); 
END; 
/

任何帮助将感激这么多

来源

2017-09-26 Ras Rass

你怎么从这些默认值我有可能产生IP地址是什么意思？您是否只需要IP地址> 12.123.60.256的完整IP4地址范围？不知道你在做什么。 – xQbert

我的意思是我有IP号码的默认值。它是12.123.60.165。然后我必须生成新的IP号码，分别是12.123.60.167,12.123.60.168,12.123.60.169等等。直到以（256）12.123.60.256结尾。直到IP数量的最大IP数将是256.256.256.256。 –

生成4,213,638,225条记录......这就是40亿2.13亿美元需要一些时间。但是有256个记录的表的4个交叉连接似乎工作;而你的起始IP只会消除约14,612,400条记录;或0.3456％不要指望它很快......但你可以用这些＃表创建一个表，我想...... – xQbert

要生成一组所有IPv4的人可以使用一个交叉连接和CTE与16条记录和交叉连接。但是我还不确定你真的是什么。

with cte (A) as (
SELECT 0 from dual UNION ALL 
SELECT 1 from dual UNION ALL 
SELECT 2 from dual UNION ALL 
SELECT 3 from dual UNION ALL 
SELECT 4 from dual UNION ALL 
SELECT 5 from dual UNION ALL 
SELECT 6 from dual UNION ALL 
SELECT 7 from dual UNION ALL 
SELECT 8 from dual UNION ALL 
SELECT 9 from dual UNION ALL 
SELECT 10 from dual UNION ALL 
SELECT 11 from dual UNION ALL 
SELECT 12 from dual UNION ALL 
SELECT 13 from dual UNION ALL 
SELECT 14 from dual UNION ALL 
SELECT 15 from dual), 
--Get data set for 0 to 255 numbers. 
Get256Range as (SELECT row_number() over (order by A.A)-1 seg 
    FROM CTE A 
    CROSS JOIN cte B) 
--Now cross join the 256 4 times for each class of Ip. 

SELECT A.Seg ||'.'|| B.Seg||'.'|| C.Seg||'.'||D.Seg as IPAddress 
from Get256Range A 
CROSS JOIN Get256Range B 
CROSS JOIN Get256Range C 
CROSS JOIN Get256Range D 
--Not sure what part of the "set" you need but one could change these values 
--Limited for sizing; but one could create a table of all IPv4 addresses... 
WHERE A.seg = 12 
    and B.seg = 123;

您可以根据需要包括前导零...

lpad(A.Seg,3,'0') ||'.'|| lpad(B.Seg,3,'0')||'.'|| lpad(C.Seg,3,'0')||'.'|| lpad(D.Seg,3,'0') IpAddressWithLeadZero

这让人们可以进行排序或基于特定范围过滤器

所以只能返回这些较大（不是最有效的）

WHERE lpad(A.Seg,3,'0') ||'.'|| lpad(B.Seg,3,'0')||'.'|| lpad(C.Seg,3,'0')||'.'|| lpad(D.Seg,3,'0') >='012.123.060.165'

可能更为有效：

WHERE (A.Seg = 12 and B.Seg = 123 and C.Seg = 60 and D.Seg > 165) OR (A.Seg = 12 and B.Seg = 123 and C.Seg > 60) OR (A.Seg = 12 and B.Seg > 123) OR (A.Seg > 12)

来源

2017-09-26 13:47:31 xQbert

您可以使用DBMS_RANDOM包生成随机值。您需要此软件包的特权。例如：：

SQL> select trunc(dbms_random.value(12,256)) ip1, 
    2  trunc(dbms_random.value(123,256)) ip2, 
    3  trunc(dbms_random.value(60,256)) ip3, 
    4  trunc(dbms_random.value(165,256)) ip4 
    5* from dual 

    IP1  IP2  IP3  IP4 
---------- ---------- ---------- ---------- 
    156  163   78  231

或者在循环中生成。这样的事情：

declare 
    ip1 int; 
    ip2 int; 
    cnt int := 0; 
begin 
    for i in 12..256 loop 
    ip1 := i; 
    for j in 123..256 loop 
     ip2 := j; 
    end loop; 
    end loop; 
end; 
/

来源

2017-09-26 03:52:44

dbms_random随机产生IP。但我想要它随机产生的。在结构化1,2,3,4,5 ...无论如何非常感谢你的回复花花公子 –

然后我们可以使用循环。我在答案中添加了一个例子 –

在oracle中生成IP地址

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