我想在同一页面上显示登录和注册表单。然而,似乎我们无法在控制器的不同的两个动作中使用不同的表单变量来呈现相同的模板。使用Symfony 3在同一页上呈现多个表单
这是我的意思;
class SecurityController extends Controller {
/**
* @Route("/", name="login")
*/
public function loginAction(Request $request)
{
//Check if the user is already authenticated
if($this->container->get('security.authorization_checker')->isGranted('IS_AUTHENTICATED_FULLY')) {
return $this->redirect($this->generateUrl('dashboard'));
}
$authenticationUtils = $this->get('security.authentication_utils');
// get the error if there is one
$error = $authenticationUtils->getLastAuthenticationError();
// last username entered by the user
$lastUsername = $authenticationUtils->getLastUsername();
$this->addFlash(
'welcome',
'Welcome back!'
);
return $this->render(
'::landing.html.twig',
array(
// last username entered by the user
'last_username' => $lastUsername,
'error' => $error,
)
);
$registrationform = $this->get('form.factory')->createNamedBuilder('registrationform', UserType::class);
}
/**
* @Route("/register", name="register")
*/
public function registerAction(Request $request)
{
//Check authentication
if($this->container->get('security.authorization_checker')->isGranted('IS_AUTHENTICATED_FULLY')) {
return $this->redirect($this->generateUrl('dashboard'));
}
// get the authentication utils
$authenticationUtils = $this->get('security.authentication_utils');
// get the login error if there is one
$error = $authenticationUtils->getLastAuthenticationError();
// last username entered by the user
$lastUsername = $authenticationUtils->getLastUsername();
// build the form
$user = new User();
$form = $this->createForm(UserType::class, $user);
// handle the submit (will only happen on POST)
$form->handleRequest($request);
if ($form->isSubmitted() && $form->isValid()) {
$user->setRoles(array('ROLE_USER'));
// Encode the password (you could also do this via Doctrine listener)
$password = $this->get('security.password_encoder')
->encodePassword($user, $user->getPlainPassword());
$user->setPassword($password);
// save the User!
$em = $this->getDoctrine()->getManager();
$em->persist($user);
$em->flush();
$token = new UsernamePasswordToken($user, null, 'main', $user->getRoles());
$this->get('security.token_storage')->setToken($token);
$this->get('session')->set('_security_main', serialize($token));
// ... do any other work - like sending them an email, etc
// maybe set a "flash" success message for the user
$this->addFlash(
'success',
'Please complete your profile now.'
);
$message = \Swift_Message::newInstance()
->setSubject('You have successfully signed up!')
->setFrom('[email protected]')
->setTo($user->getUsername())
->setBody($this->renderView(
':emails:registration.html.twig'),'text/html');
$this->get('mailer')->send($message);
return $this->redirectToRoute('update');
} else{
$errors = $this->get('validator')->validate($user);
}
return $this->render(
'::landing.html.twig',
array('form' => $form->createView(),
'last_username' => $lastUsername,
'error' => $error,
)
);
}
}
上面我有我的登录和注册动作。我想将“表单”变量传递给我使用登录操作呈现的相同的树枝模板。当我尝试这样做时,我收到以下异常。
Variable "form" does not exist in ::landing.html.twig at line 50
500 Internal Server Error - Twig_Error_Runtime
您没有传递任何'form'变量在'loginAction'视图。你注意到了吗?这就是你得到错误的原因。 – Lumen
是的。抱歉忘记在发布之前删除该更新。现在我更新了这个问题。我试图在两个操作中呈现相同的模板。 – mburakergenc