3
我有一张地图,显示带有某些标记的KML矢量图层。当你点击标记时,它弹出一个信息框。我希望能够根据传入页面的参数自动弹出一个信息框。 我想我需要通过使用getFeaturesByAttribute()来查找名称,但features数组似乎总是空的。 (虽然我能看到的内容,当我使用Firebug)OpenLayers功能阵列为空
什么我需要做的就是数组中的项?
代码:
function init()
{
var options = {
projection: new OpenLayers.Projection("EPSG:900913"),
displayProjection: new OpenLayers.Projection("EPSG:4326"),
units: "m",
};
map = new OpenLayers.Map('map', options);
var mapnik = new OpenLayers.Layer.OSM("OpenStreetMap");
var gmap = new OpenLayers.Layer.Google("Google", {sphericalMercator:true});
var gsat = new OpenLayers.Layer.Google(
"Google Satellite",
{type: google.maps.MapTypeId.SATELLITE, numZoomLevels: 22}
);
groups = new OpenLayers.Layer.Vector("Groups", {
projection: map.displayProjection,
strategies: [new OpenLayers.Strategy.Fixed()],
protocol: new OpenLayers.Protocol.HTTP({
url: "http://maps.google.co.uk/maps/ms?msa=0&msid=210450558816094618535.0004bd79ceb30e9acb9da&output=kml",
format: new OpenLayers.Format.KML({
extractStyles: true,
extractAttributes: true
})
})
});
map.addLayers([mapnik, gmap, gsat, groups]);
select = new OpenLayers.Control.SelectFeature(groups);
groups.events.on({
"featureselected": onFeatureSelect,
"featureunselected": onFeatureUnselect
});
map.addControl(select);
select.activate();
map.addControl(new OpenLayers.Control.LayerSwitcher());
var center = new OpenLayers.LonLat(-2.58789,51.52283).transform(map.displayProjection, map.projection);
var zoom = 12
map.setCenter(center, zoom);
alert(groups.features.length); // is always 0
}
谢谢,工作出色! – Paul 2012-04-18 08:09:59