2012-05-14 48 views
0

我有一个网址“http://184.82.158.234/~store/rest/system/connect.json”和发布此网址与mozilla插件称为海报返回数据的形式json 我想要的是从Android发布此网址以将该json数据转换为android视图。从Android发布URL来检索数据

任何帮助,高度赞赏 感谢

回答

1
public void postData() { 
// Create a new HttpClient and Post Header 
HttpClient httpclient = new DefaultHttpClient(); 
HttpPost httppost = new HttpPost("http://184.82.158.234/~store/rest/system/connect.json"); 

try { 
    // Add your data 
    List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2); 
    nameValuePairs.add(new BasicNameValuePair("id", "12345")); 
    httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs)); 

    // Execute HTTP Post Request 
    HttpResponse response = httpclient.execute(httppost); 

} catch (ClientProtocolException e) { 
    // TODO Auto-generated catch block 
} catch (IOException e) { 
    // TODO Auto-generated catch block 
} 
} 

响应变量将包含您的JSON数据。

+1

的兄弟,我已经尝试过乌拉圭回合的解决方案不工作的感谢答复 –

+1

和U可以PLZ告诉我Ÿ我不得不这样做 nameValuePairs.add(新BasicNameValuePair(“ID”,“12345”)); 因为我的网址不采取任何参数它只是返回数据没有任何参数 –

+1

你不能解析json吗?你可以扩大你的问题多一点 –

1

查看下面的代码:试试这可能会帮助你。

ArrayList nameValuePairs1 = new ArrayList(); 

     nameValuePairs1.add(new BasicNameValuePair("user_id", "")); 
     nameValuePairs1.add(new BasicNameValuePair("product_id", "")); 
     nameValuePairs1.add(new BasicNameValuePair("product_review",""+text)); 

     HttpClient httpclient = new DefaultHttpClient(); 

     HttpPost httppost = new HttpPost(URL); 

     httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs1)); 

     HttpResponse responce = httpclient.execute(httppost); 

     HttpEntity entity = responce.getEntity(); 

     is = entity.getContent(); 

     BufferedReader bufr = new BufferedReader(new InputStreamReader(is1,"iso-8859-1"), 8); 

     StringBuilder sb = new StringBuilder(); 

     sb.append(bufr.readLine() + "\n"); 

     String line = "0"; 

     while ((line = bufr.readLine()) != null) 

     { 

     sb.append(line + "\n"); 

     } 

     is1.close(); 

     result = sb.toString(); 

结果是一个json字符串。解析该json并在任何控件中显示。我在文本视图中显示了这一点,见下文。

+1

好吧,让我试试 你可以告诉我这是什么?代码 nameValuePairs1.add(new BasicNameValuePair(“user_id”,“”)); nameValuePairs1.add(new BasicNameValuePair(“product_id”,“”)); nameValuePairs1.add(new BasicNameValuePair(“product_review”,“”+ text));'code' 因为我得到的响应没有任何参数 –

+1

这是你必须发送的参数, www.xyz.com?name=dhaval&product_id=1&product_review=4。这是get方法,但如果你想使用post方法,那么你必须传递数组中的数据,就像我在使用nameValuePairs1数组的答案中写的一样。 –

+0

*** *** 05-14 17:35:50.541:E/AndroidRuntime(1216):java.lang.RuntimeException:无法启动活动ComponentInfo {com.post/com.post.PostActivity}:android.os.NetworkOnMainThreadException * * 这是让我的应用程序崩溃,我不知道如何解决它 帮助plzzz –

1

这里是一个函数,也许你可以用来发布一个字符串到一个URL。

public String doHttpPost(final String fullUrl, final String body) { 

     final URL url = new URL(fullUrl); 

     final HttpURLConnection urlConnection = (HttpURLConnection) url.openConnection(); 

     // set the request mode as POST 
     urlConnection.setRequestMethod("POST"); 

     urlConnection.setUseCaches(false); 
     urlConnection.setDoOutput(true); 

     urlConnection.setRequestProperty("Accept-charset", "utf-8"); 
     urlConnection.setRequestProperty("Content-type", "application/x-www-form-urlencoded"); 

     final DataOutputStream request = new DataOutputStream(urlConnection.getOutputStream()); 

     // write the body. 
     request.writeBytes(body); 

     // flush output buffer 
     request.flush(); 
     request.close(); 

     // construct a read using input stream and charset. 
     final InputStreamReader isr = new InputStreamReader(urlConnection.getInputStream(), CHARSET_UTF8); 
     final BufferedReader in = new BufferedReader(isr); 

     String inputLine; 
     final StringBuilder stringBuilder = new StringBuilder(); 
     while ((inputLine = in.readLine()) != null) { 
      stringBuilder.append(inputLine).append("\n"); 
     } 

     in.close(); 
     isr.close(); 

     urlConnection.disconnect(); 

     return stringBuilder.toString(); 
}