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我的应用程序的用户将被测试他们的英语。他们将通过在该单词旁边放置复选标记来从列表中选择不同的单词。他们只想选择名词的单词。例如,如果他们正确选择了5个,我该如何向他们展示50%的分数。我认为我需要根据用户的输入过滤字典值。用户的输入是一个数组。对此进行编码的最佳方式是什么?Swift 3 - 用字典值匹配用户输入
我的应用程序的用户将被测试他们的英语。他们将通过在该单词旁边放置复选标记来从列表中选择不同的单词。他们只想选择名词的单词。例如,如果他们正确选择了5个,我该如何向他们展示50%的分数。我认为我需要根据用户的输入过滤字典值。用户的输入是一个数组。对此进行编码的最佳方式是什么?Swift 3 - 用字典值匹配用户输入
试试下面的代码: - 100%的工作
let myDictionary : [String : Any] =
[ "Nouns":["One","Two","Three","Four","Five","Six","Seven","Eight","Nine","Ten"],
"Verbs":["Eat","play","dance","walk","run","sing","read","write","go","come"]]
var myUserSelectedArray:[String] = ["One","come","Three","go","Five","x","Six","x","x","Ten"];
let myNounArray = myDictionary["Nouns"] as? [String];
let myVerbArray = myDictionary["Verbs"] as? [String];
let set1:Set<String> = Set(myUserSelectedArray);
let set2:Set<String> = Set(myNounArray!);
let set3:Set<String> = Set(myVerbArray!);
let scroeInNoun = set1.intersection(set2).count;
let scroeInVerb = set1.intersection(set3).count;
print ("score in Verb \((scroeInVerb * 100)/set2.count) %")
print ("score in noun \((scroeInNoun * 10)/set3.count) %")
let finalScore = (scroeInNoun + scroeInVerb) * 100/((myNounArray?.count)! + (myVerbArray?.count)!)
print ("final score in noun \(finalScore) %")
如果对你有用请接受答案
谢谢!伟大的代码! – salanthonyc
是使用简单的数学公式(正确答案* 100)/总问问题 –