2012-02-24 46 views
0

我想在单个查询中获取我的手机联系人姓名,电话号码和电子邮件地址。有可能获取1查询中的所有内容吗?联系人显示时应用程序挂起

我有我的手机和其get忌用几乎1000个联系人,当我尝试下面的代码行,以显示我的联系方式:

Cursor cursor = this.getContentResolver().query(intent.getData(), null, null, null,null); 
while (cursor.moveToNext()) 
{   
    String contactId = cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts._ID));   
    hasPhone = cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER)); 
    if (hasPhone.equalsIgnoreCase("1")) 
     hasPhone = "true"; 
    else 
     hasPhone = "false" ; 

    if (Boolean.parseBoolean(hasPhone)) 
    { 
     Cursor phones = getContentResolver().query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI, 
       null,ContactsContract.CommonDataKinds.Phone.CONTACT_ID +" = "+ contactId,null, 
       ContactsContract.Contacts.DISPLAY_NAME + " COLLATE NOCASE"); 
     while (phones.moveToNext()) 
     { 
      String phoneNumber = phones.getString(phones.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER)); 
      String name = phones.getString(phones.getColumnIndexOrThrow(ContactsContract.Contacts.DISPLAY_NAME));         
     } 
     phones.close(); 
    } 
    // Find Email Addresses 
    Cursor emails = getContentResolver().query(ContactsContract.CommonDataKinds.Email.CONTENT_URI,null, 
     ContactsContract.CommonDataKinds.Email.CONTACT_ID + " = " + contactId,null, 
     ContactsContract.Contacts.DISPLAY_NAME + " COLLATE NOCASE");// contactId+ " DESC"); 
    while (emails.moveToNext()) 
    { 
     String emailAddress = emails.getString(emails.getColumnIndex(ContactsContract.CommonDataKinds.Email.DATA));    
     String name = cursor.getString(cursor.getColumnIndexOrThrow(ContactsContract.Contacts.DISPLAY_NAME));    
    } 
    emails.close(); 
    } //while (cursor.moveToNext()) 
+0

请张贴在调用此方法的代码.... – 2012-02-24 10:00:10

回答

1

做在的AsyncTask ...总是时间的首选方式耗时的过程...

我有同样的问题,当我有大约500个联系人。我这么做是的AsyncTask和它的工作很好..

+0

我已经c在异步任务中调用了这个函数。 doInBackground() – Monali 2012-02-24 06:35:39

+0

@Monali as ntc said在AsyncTask中执行它会正常工作 – Piyush 2012-02-24 06:52:14

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