读一个CSV文件将字符串转换为浮动

-2

行1：

[-0.74120803 0.6338942 ],[-1.01583889 0.20901699],[-1.02969154 0.14459244],[ 0.10362657 0.31347394],[ 1.69977092 -0.13384537],[ 1.39789431 -0.52155783],[ 0.02928792 0.24156825],[-1.03616494 0.33943 ],[ 0.84921822 0.47879992],[ 0.279905 0.96184517],[ 0.43602597 -0.27275052],[ 1.4766132 -0.48128695],[ 0.96219625 -0.44950686],[ 0.24356381 -0.0253022 ],[ 0.09346193 0.07808998],[ 0.26571546 -0.1678716 ],[ 0.03055046 1.05913456],[ 1.94137487e+00 -1.57339675e-03],[ 0.22311559 0.98762516],[ 2.00176133 0.13017485],......

注意，数据是两行：第一行包含x和y坐标，第二行包含它们的标志状态。

行2

0,0,0,1,1,1,1,0,0,0,1,1,1,1,1,1,0,1,0,1,1,0,0,1,0,0,0,1,0,1,0,0,1,1,1,0,0,1,0,1,1,0,0,0,1,1,1,1,0,1,0,0,0,0,0,0,0,0,1,0,0,0,1,1,1,0,0,1,1,.......

我想将数据存储在3所列出：x，y和flag。感谢您对此部分的帮助。

来源

2017-02-14 Kshitij Garg

请发布一些您已经开始使用的代码，以及您遇到的确切问题，以便我们可以帮助您进行调试。 –

引用与代码格式有很大区别 – Dan

您使用的Python版本是2或3？ – martineau

row1 = '[-0.74120803 0.6338942 ],[-1.01583889 0.20901699],[-1.02969154 0.14459244],[ 0.10362657 0.31347394],[ 1.69977092 -0.13384537],[ 1.39789431 -0.52155783],[ 0.02928792 0.24156825],[-1.03616494 0.33943 ],[ 0.84921822 0.47879992],[ 0.279905 0.96184517],[ 0.43602597 -0.27275052],[ 1.4766132 -0.48128695],[ 0.96219625 -0.44950686],[ 0.24356381 -0.0253022 ],[ 0.09346193 0.07808998],[ 0.26571546 -0.1678716 ],[ 0.03055046 1.05913456],[ 1.94137487e+00 -1.57339675e-03],[ 0.22311559 0.98762516],[ 2.00176133 0.13017485]' 
row2 = '0,0,0,1,1,1,1,0,0,0,1,1,1,1,1,1,0,1,0,1' 

l = [] 

for xy, flag in zip(row1.split(','), row2.split(',')): 
    x, y = xy.strip('[] ').split(' ') 
    l.append((float(x), float(y), int(flag))) 

print l

如果您prefere 3名独立的名单：

row1 = '[-0.74120803 0.6338942 ],[-1.01583889 0.20901699],[-1.02969154 0.14459244],[ 0.10362657 0.31347394],[ 1.69977092 -0.13384537],[ 1.39789431 -0.52155783],[ 0.02928792 0.24156825],[-1.03616494 0.33943 ],[ 0.84921822 0.47879992],[ 0.279905 0.96184517],[ 0.43602597 -0.27275052],[ 1.4766132 -0.48128695],[ 0.96219625 -0.44950686],[ 0.24356381 -0.0253022 ],[ 0.09346193 0.07808998],[ 0.26571546 -0.1678716 ],[ 0.03055046 1.05913456],[ 1.94137487e+00 -1.57339675e-03],[ 0.22311559 0.98762516],[ 2.00176133 0.13017485]' 
row2 = '0,0,0,1,1,1,1,0,0,0,1,1,1,1,1,1,0,1,0,1' 

listX, listY = [], [] 

for xy in row1.split(','): 
    x, y = xy.strip('[] ').split(' ') 
    listX.append(float(x)) 
    listY.append(float(y)) 

listFlag = [int(flag) for flag in row2.split(',')] 

print listX, listY, listFlag

来源

2017-02-14 18:10:01

两个单行会做：

flags = [int(x) for x in row2.split(',')] 
x, y = zip(*((float(value) for value in entry[1:-1].split()) for entry in row1.split(',')))

现在：

print(flags[:5]) 
print(list(x[:5])) 
print(list(y[:5]))

输出：

[0, 0, 0, 1, 1] 
[-0.74120803, -1.01583889, -1.02969154, 0.10362657, 1.69977092] 
[0.6338942, 0.20901699, 0.14459244, 0.31347394, -0.13384537]

来源

2017-02-14 18:56:45

读一个CSV文件将字符串转换为浮动

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