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我想访问按钮元素(div)的父节点,但每次都收到错误。这是我想要做的。简而言之,这是一个有2个div的页面。我只想要一次显示一个div。第一页上有一个按钮,它切换到第二个按钮,第二个按钮应该返回到第一个按钮(但不是因为它无法找到父节点)。使用按钮访问父节点
<div class="pageContent" id="page_3">
<div class="primaryPage" id="primaryPage_3">
<h2>Bills_______________________</h2>
<p>Here are my monthly Bills<br><br>blah blah</p>
<button type="button" id="billButton" onclick="newBill()">Add Bill</button>
</div>
<div class="pageContent" id="billPage">
<p>this is the bill page</p>
<button class="backButton" onclick="back()">Back</button>
</div>
</div>
function newBill(){
document.getElementById("primaryPage_3").style.display = "none";
document.getElementById("billPage").style.display = "block";
document.getElementById("billPage").setAttribute("back", "primaryPage_3");
}
function back(){
var previousPage = this.parentNode.getAttribute("back");
this.parentNode.style.display = "none";
document.getElementById(previousPage).style.display = "block";
}
这样做,谢谢! – 2012-07-17 04:22:51