Xcode TableViewCell推送到ViewController

我正在创建一个应用程序，在其中显示餐桌列表，并且当您单击其中一个时，它会更详细地显示膳食。Xcode TableViewCell推送到ViewController

当我运行它，它会显示在桌子上吃饭，但是当我点击了一顿它只是提供了一顿模板，

This is a picture of the storyboard 这里是我使用的代码为我TableViewController显示项目

private func loadSampleMeals() { 

     let photo1 = UIImage(named: "Sprite") 
     let photo2 = UIImage(named: "HotCheetos") 
     let photo3 = UIImage(named: "Nachos") 

     guard let meal1 = Meal(name: "Sprite", price: "$1.50", photo: photo1, rating: 0, calories: "Calories: 129", description: "Description: A refreshing lemon-lime soda") else { 
      fatalError("Unable to instantiate meal1") 
     } 

     guard let meal2 = Meal(name: "Hot Cheetos", price: "$1.50", photo: photo2, rating: 0, calories: "Calories: 160", description: "Description: A spicy version of original cheetos") else { 
      fatalError("Unable to instantiate meal2") 
     } 

     guard let meal3 = Meal(name: "Nachos", price: "$1.50", photo: photo3, rating: 0, calories: "Calories: 436", description: "Description: Tortilla chips with a side of smooth nacho cheese") else { 
      fatalError("Unable to instantiate meal2") 
     } 

     meals += [meal1, meal2, meal3] 
    } 


     override func prepare(for segue: UIStoryboardSegue, sender: Any?) { 
     super.prepare(for: segue, sender: sender) 

     switch(segue.identifier ?? "") { 
      case "ShowDetail": 
      guard let mealDetailViewController = segue.destination as? MealViewController else { 
        fatalError("Unexpected destination: \(segue.destination)") 
      } 

      guard let selectedMealCell = sender as? MealTableViewCell else { 
       fatalError("Unexpected sender: \(sender)") 
      } 

      guard let indexPath = tableView.indexPath(for: selectedMealCell) else { 
       fatalError("The selected cell is not being displayed by the table") 
      } 

      let selectedMeal = meals[indexPath.row] 
      mealDetailViewController.meal = selectedMeal 

     default: 
      fatalError("Unexpected Segue Identifier; \(segue.identifier)") 
     } 
    }

在代码中，保护报表应使其显示在视图控制器的项目数据，但我得到了默认的错误在底部

来源

2017-04-01 oliverJaros

您是否通过数据，而改变tableview控制器到详细控制器？ –

你可以用你的tableView方法显示一些代码，它会告诉我们你正在做什么 –

删除顶部导航控制器...在应用程序中应该只有1个导航控制器... –

您可以01访问了一顿对象，例如，你有一个餐饮生成阵列只有一个部分

var meals: [Meal] 

func numberOfSections(in tableView: UITableView) -> Int { 
    return 1 
} 

func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int { 
    return meals.count 
} 

func tableView(_ tableView: UITableView, didSelectRowAt indexPath: IndexPath) { 
    let selectedMeal = meals[indexPath.row] 
    let mealDetailsVC = MealDetailsViewController() 
    mealDetailsVC.meal = selectedMeal 

    navigationController?.pushViewController(mealDetailsVC, animated: true) 
}

来源

2017-10-09 02:12:12 imaduddinaf

Xcode TableViewCell推送到ViewController

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