合并两个对象数组并获取唯一对象PHP

这是示例代码我有

$tasks = array(); 
    $task_user = new Task_User; 
    $task_user->setUserId($this->session_data['userId']); 
    $user_taskIds = $this->getUserTasks($task_user); 
    foreach ($user_taskIds as $row) { 
     $task = new Task; 
     // $task->setBranchId($branch_id); 
     $task->setTaskId($row->getTaskId()); 
     $tasks[] = $this->getTask($task); 
    } 
    echo "<pre>"; 
    print_r($tasks); 
    $pageData['userTasks'] = $tasks; 
    $task = new Task; 
    // $task->setBranchId($branch_id); 
    $task->setCreated($this->session_data['userId']); 
    $tasks1 = $this->getBranchTasks($task); 
    if (!empty($tasks1[0])) 
    { 
     $pageData['userTasks'] = $tasks1; 
    } 
    print_r($tasks1); 
    print_r($pageData['userTasks']);

$这 - >负载>视图（ '家'，$ pageData）;

OUTPUT：

Array 
(
    [0] => Task Object 
     (
      [task_id:Task:private] => 22 
      [service_id:Task:private] => 1 
      [branch_id:Task:private] => 1 
      [customer_id:Task:private] => 121 
      [lead_id:Task:private] => 0 
      [name:Task:private] => YTY0000022 
     ) 

    [1] => Task Object 
     (
      [task_id:Task:private] => 24 
      [service_id:Task:private] => 1 
      [branch_id:Task:private] => 1 
      [customer_id:Task:private] => 1046 
      [lead_id:Task:private] => 0 
      [name:Task:private] => YTY0000024 
     ) 

) 
Array 
(
    [0] => Task Object 
     (
      [task_id:Task:private] => 9 
      [service_id:Task:private] => 1 
      [branch_id:Task:private] => 1 
      [customer_id:Task:private] => 599 
      [lead_id:Task:private] => 0 
      [name:Task:private] => YTY0000009 
     ) 

    [1] => Task Object 
     (
      [task_id:Task:private] => 10 
      [service_id:Task:private] => 1 
      [branch_id:Task:private] => 1 
      [customer_id:Task:private] => 313 
      [lead_id:Task:private] => 0 
      [name:Task:private] => YTY0000010 
     ) 

) 
Array 
(
    [0] => Task Object 
     (
      [task_id:Task:private] => 9 
      [service_id:Task:private] => 1 
      [branch_id:Task:private] => 1 
      [customer_id:Task:private] => 599 
      [lead_id:Task:private] => 0 
      [name:Task:private] => YTY0000009 
     ) 

    [1] => Task Object 
     (
      [task_id:Task:private] => 10 
      [service_id:Task:private] => 1 
      [branch_id:Task:private] => 1 
      [customer_id:Task:private] => 313 
      [lead_id:Task:private] => 0 
      [name:Task:private] => YTY0000010 
     ) 

)

所以，最后我需要的对象的两个阵列应与唯一对象进行组合，并将其传递到一个阵列。我从最近6个小时试过了。但我无法得到它。请帮助我在此先感谢。

来源

2015-12-02 Ravi

你可以修改任务类？如果这样安排它告诉你的ID。另一种获取私有数据的方法是“序列化”任务并将其从字符串中挖掘出来？ –

如果它们是相同的对象，那么[spl_object_hash - 返回给定对象的哈希ID]（http://php.net/manual/en/function.spl-object-hash.php）可能有用吗？ –

在一些简短的测试中，它看起来比in_array适用于对象。但是如果没有揭露它们，它将无法观察私有变量，这是我留给你的一个练习。

$tasks2 = []; 
foreach($tasks as $t){ 
    if(!in_array($t,$tasks2){ 
     array_push($tasks2,$t); 
    } 
}

来源

2015-12-02 11:18:23 r3wt

如果您看到代码，我将$ tasks和$ tasks1推入单个数组中。然后重写 – Ravi

否您没有。你完全替换了数组'$ pageData ['userTasks'] = $ tasks1;' –

替换该行 ...

if (!empty($tasks1[0])) 
{ 
    $pageData['userTasks'] = $tasks1; 
} 
...

到 ...

if (!empty($tasks1[0])) 
{ 
    $pageData['userTasks'] = array_replace($pageData['userTasks'], $tasks1); 
} 
...

来源

2015-12-02 11:37:34

如果我使用这个 – Ravi

你告诉我会发生什么。你试过了吗？ –

合并两个对象数组并获取唯一对象PHP

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