在SQL Server中查找顶部行的SQL查询

Question

在SQL Server中，我试图获得前5名工资。

我的工资就像

5000 
5000 
4500 
4500 
3000 
2000 
1000 
500 
400 

，我想获得

5000 
5000 
4500 
4500 
3000 
2000 
1000 

Answer 1

如果你想获得前5名不同的工资（不论相同金额可能有多少次出现），您需要使用DENSE_RANK()排名功能和CTE来实现这一目标：

DECLARE @salaries TABLE (salary DECIMAL(18,4)) 

INSERT INTO @salaries VALUES(5000) 
INSERT INTO @salaries VALUES(5000) 
INSERT INTO @salaries VALUES(4500) 
INSERT INTO @salaries VALUES(4500) 
INSERT INTO @salaries VALUES(3000) 
INSERT INTO @salaries VALUES(2000) 
INSERT INTO @salaries VALUES(1000) 
INSERT INTO @salaries VALUES(500) 
INSERT INTO @salaries VALUES(400) 

;WITH SalariesRanked AS 
(
    SELECT 
     Salary, 
     SalaryNumber = DENSE_RANK() OVER(ORDER BY Salary DESC) 
    FROM  
     @salaries 
) 
SELECT salary 
FROM SalariesRanked 
WHERE SalaryNumber <= 5 

这导致输出这样的：

salary 
5000.0000 
5000.0000 
4500.0000 
4500.0000 
3000.0000 
2000.0000 
1000.0000 

Answer 2

SELECT TOP 5 salary FROM your_table 
ORDER BY salary DESC 

Answer 3

看一看使用TOP (Transact-SQL)

Answer 4

select salary 
from 
    (
    select salary, 
      dense_rank() over(order by salary desc) as rn 
    from YourTable 
) as T 
where rn <= 5 

尝试在SE-Data

Answer 5

SELECT TOP 5 Salary 
FROM [Table] 
GROUP BY Salary 
ORDER BY Salary DESC 

---

您需要组查询，以避免重复小号alaries。