Java - 为什么不行？

Question

这只是一个简单的摇滚纸剪刀游戏，我用日食作为测试，我已经把一个通过此网站较早，并得到一些答案，但现在我遇到了一个问题，我找不到赢家？

package rockPaperScissors; 

import java.util.Scanner; 
import java.util.Random; 

public class RockPaperScissors { 

    public static void main(String args[]) { 
     String playerChose; 
     String computerChose; 
     while(true) { 
      System.out.println("Welcome to rock paper scissors!"); 
      System.out.println("Please enter \"rock\", \"paper\", or \"scissors\""); 
      Scanner playerChoice = new Scanner (System.in); 
      playerChose = playerChoice.nextLine(); 
      Random computerChoice = new Random(); 
      int computer = computerChoice.nextInt(3) + 1; 

      switch (computer) { 
      case 1: 
       computerChose = "rock"; 
       System.out.println("Computer chose rock!"); 
       break; 
      case 2: 
       computerChose = "paper"; 
       System.out.println("Computer chose paper!"); 
       break; 
      case 3: 
       computerChose = "scissors"; 
       System.out.println("Computer chose scissors!"); 
      } 

      computerChose = new String(); 

      if (playerChose.equals("rock") && computerChose.equals("scissors") || playerChose.equals("paper") && computerChose.equals("rock") || playerChose.equals("scissors") && computerChose.equals("paper")) { 
       System.out.println("Player won!"); 
      } 
      if(playerChose.equals(computerChose)) { 
       System.out.println("Game tied!"); 
      } 
      if(computerChose.equals("rock") && playerChose.equals("scissors") || computerChose.equals("paper") && playerChose.equals("rock") || computerChose.equals("scissors") && computerChose.equals("paper")) { 
       System.out.println("Computer won!"); 
      } 
     } 
    } 
} 

Answer 1

测试和工程

初始化computerChose向右走，让你在初始化后，它改变
String computerChose;到String computerChose = "";

并带走行computerChose = new String();因为它设置computerChoose字符串为空字符串你的开关盒。

Answer 2

更改您的computerChose初始申报（您while前），以String computerChose = "";并删除读取computerChose = new String();（您switch后）线。

Answer 3

在while声明后，computerChose正在使用computerChose = newString()重置。因此，在if声明中没有测试的条件都等同于真实。