是否可以将我的SQL复制定义导出到XML？

Question

我被要求这样做，但我不知道是否有这样做的标准方式。有谁知道是否有方法在SQL Server中导出？

Answer 1

AFIK没有这样做的标准方法。作为技术的复制早于XML，其工具集和元数据不是以XML为中心的。但是，与复制相关的所有内容都存储在表的某处，无论是在主数据库还是在msdb或分发数据库中，请参见Replication Tables topic on MSDN或复制DMV（sys.dm_repl_articles和sys.dm_repl_schemas）。所有这些信息都可以用XML格式化和格式化，但我不知道覆盖这些信息的任何标准XML模式。

Answer 2

Remus的回答非常好。这是我用来将它导出到XML的SQL脚本。希望它对其他人有用：

DECLARE @PublicationId INT 
SET @PublicationId = 1 –- Use your publication ID here. Use SELECT * FROM syspublications to see a list of publications 

select 
     Publication.name AS [Name] 
     , Publication.description AS [Description] 
     , Article.name AS [Name] 
     , Article.dest_table AS [Table] 
     , [Column].name AS [Name] 
     , [Column].[Type] 
     , [Column].MaxLength 
     , [Column].Nullable 
from dbo.syspublications Publication 
     join dbo.sysarticles Article on Publication.pubid = Article.pubid 
      join sys.tables st on st.object_id = Article.objid 
     join dbo.sysarticlecolumns ac on Article.artid = ac.artid 
     join 
     (
      select 
        sc.object_id 
        , sc.column_id 
        , sc.name AS [Name] 
        , sty.name AS [Type] 
        , sc.max_length AS MaxLength 
        , sc.is_nullable AS Nullable 
      from dbo.syspublications p 
        join dbo.sysarticles a on p.pubid = a.pubid 
        join dbo.sysarticlecolumns ac on a.artid = ac.artid 
         join sys.columns sc on sc.object_id = a.objid AND sc.column_id = ac.colid 
        join sys.types sty on sty.user_type_id = sc.user_type_id 
      where p.pubid = @PublicationId 
    ) [Column] on [Column].object_id = Article.objid AND [Column].column_id = ac.colid 
where Publication.pubid = @PublicationId FOR XML AUTO