2017-10-18 114 views
0

我想使用Spark Web框架版本2.6.0,JSF 2.2,Jstl 1.2在Java 8中创建一个restful api,我希望将它部署在Tomcat服务器8.5.9上。我有这样的配置在web.xml中我:在Tomcat上使用Spark Web框架的RESTful服务

<?xml version="1.0" encoding="UTF-8"?> 
<web-app version="3.1" xmlns="http://xmlns.jcp.org/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_3_1.xsd"> 
    <filter>   
     <filter-name>SparkFilter</filter-name> 
     <filter-class>spark.servlet.SparkFilter</filter-class> 
     <init-param> 
      <param-name>applicationClass</param-name> 
      <param-value>ec.apicorreo.filtro.InicioSpark</param-value>    
     </init-param>  
    </filter> 
    <filter-mapping>   
     <filter-name>SparkFilter</filter-name> 
     <url-pattern>/*</url-pattern> 
    </filter-mapping> 
    <context-param> 
     <param-name>javax.faces.PROJECT_STAGE</param-name> 
     <param-value>Production</param-value> 
    </context-param> 
    <servlet> 
     <servlet-name>Faces Servlet</servlet-name> 
     <servlet-class>javax.faces.webapp.FacesServlet</servlet-class> 
     <load-on-startup>1</load-on-startup> 
    </servlet> 
    <servlet-mapping> 
     <servlet-name>Faces Servlet</servlet-name> 
     <url-pattern>*.xhtml</url-pattern> 
    </servlet-mapping> 

    <welcome-file-list> 
     <welcome-file>index.xhtml</welcome-file> 
    </welcome-file-list> 
... 
... 
</web-app> 

但是我有这样的例外: javax.servlet.ServletException: Servlet execution threw an exception. 而根本原因:java.lang.StackOverflowError javax.servlet.http.HttpServletResponseWrapper.setStatus(HttpServletResponseWrapper.java:201) com.sun.faces.application.ViewHandlerResponseWrapper.setStatus(ViewHandlerResponseWrapper.java:88). 我不知道我错过了什么。

+0

貌似'setStatus'是一个递归的方法。否则,一些东西被称为一个圈 –

+0

我不处理,我只有这个过滤器:public class InicioSpark implements SparkApplication { @Override public void init(){(“/ hello”,(req ,res) - >“Hola mundo!”); } } –

+1

这似乎是一个面孔问题 –

回答