2010-11-21 42 views
0

删除记录我有三个表原发性复合键的Zend表的关系 - 从表

//1 
CREATE TABLE `client_domain` (
    `client_id` int(10) unsigned NOT NULL, 
    `domain_id` int(10) unsigned NOT NULL, 
    PRIMARY KEY (`client_id`,`domain_id`), 
    KEY `FK_client_domains_domain` (`domain_id`), 
    CONSTRAINT `FK_client_domain` FOREIGN KEY (`domain_id`) REFERENCES `domain` (`id`) ON DELETE CASCADE, 
    CONSTRAINT `FK_client_domains_client` FOREIGN KEY (`client_id`) REFERENCES `client` (`id`) ON DELETE CASCADE 
) ENGINE=InnoDB DEFAULT CHARSET=utf-8; 
//2 
CREATE TABLE `client` (
    `id` int(10) unsigned NOT NULL, 
    `name` varchar(50) NOT NULL, 
    `notes` text, 
    PRIMARY KEY (`id`) 
) ENGINE=InnoDB DEFAULT CHARSET=utf-8; 
//3 
CREATE TABLE `domain` (
    `id` int(11) unsigned NOT NULL AUTO_INCREMENT, 
    `domain_name` varchar(50) DEFAULT NULL, 
    PRIMARY KEY (`id`), 
    UNIQUE KEY `IX_domain` (`domain_name`) 
) ENGINE=InnoDB AUTO_INCREMENT=3 DEFAULT CHARSET=utf-8; 

所有工作都不错,但,当我试图使用从client_domain表中删除记录:

$del = new ClientDom(array('db' => $this->_adapter)); 
$where[] = $del->getAdapter()->quoteInto('client_id = ?', $client); 
$where[] = $del->getAdapter()->quoteInto('domain_id = ?', $domain); 
$result = $del->delete($where)->toArray(); Idelete record but with an error: 
SQLSTATE[42S22]: Column not found: 1054 Unknown column 'client_id' in 'where clause'... 

什么是错的...也是同样的事情,如果我'fetchAll($哪里)',但插入所有工作正常。

回答

2

经由解决: $ del->删除(阵列( '?CLIENT_ID ='=> $客户端, '?域ID ='=> $域 )); 不知道为什么,但通过$哪里它不工作...如果有人知道为什么...请写在这里:)