调试CakePHP保存

Question

因此，我编写了一个CakePHP 3.3应用程序，该应用程序具有“Users”表和“UserProfiles”表，并且我不能为我的生活弄清楚为什么当我从我的项目中传输项目时，代码停止工作个人发展环境到我们的托管服务器。我在使用最新的MySQL 5.7，现在我的主机报告我的数据库是Percona 5.5.51-38.2-log。实质上，我相信UserProfile无法保存，因为它找不到创建的用户。我收到的保存错误是：

SQLSTATE[23000]: Integrity constraint violation: 1452 Cannot add or update a child row: a foreign key constraint fails (`staging`.`user_profiles`, CONSTRAINT `fk_user_profiles_users` FOREIGN KEY (`user_id`) REFERENCES `users` (`id`) ON DELETE CASCADE ON UPDATE CASCADE) 

我记录的查询和我跑最后一棒显示logs\debug.log下面的语句：

2016-11-22 23:13:40 Debug: duration=1 rows=1 SELECT Users.id AS `Users__id`, Users.email AS `Users__email`, Users.password AS `Users__password`, Users.role AS `Users__role`, Users.created AS `Users__created`, UserProfiles.user_id AS `UserProfiles__user_id`, UserProfiles.address_one AS `UserProfiles__address_one`, UserProfiles.address_two AS `UserProfiles__address_two`, UserProfiles.age AS `UserProfiles__age`, UserProfiles.sex AS `UserProfiles__sex`, UserProfiles.first_name AS `UserProfiles__first_name`, UserProfiles.last_name AS `UserProfiles__last_name`, UserProfiles.city AS `UserProfiles__city`, UserProfiles.state AS `UserProfiles__state`, UserProfiles.zip AS `UserProfiles__zip`, UserProfiles.phone AS `UserProfiles__phone`, UserProfiles.photo AS `UserProfiles__photo` FROM users Users LEFT JOIN user_profiles UserProfiles ON Users.id = (UserProfiles.user_id) LIMIT 20 OFFSET 0 
2016-11-22 23:13:40 Debug: duration=0 rows=1 SELECT (COUNT(*)) AS `count` FROM users Users LEFT JOIN user_profiles UserProfiles ON Users.id = (UserProfiles.user_id) 
2016-11-22 23:13:44 Debug: duration=0 rows=0 BEGIN 
2016-11-22 23:13:44 Debug: duration=0 rows=0 SELECT 1 AS `existing` FROM users Users WHERE Users.email = 'admin1@domain.com' LIMIT 1 
2016-11-22 23:13:44 Debug: duration=0 rows=1 INSERT INTO users (email, password, role) VALUES ('admin1@domain.com', 'y$Gak.CvDbw7Jg8gwbEGBiNeVdj7L8i3xScNOoDBegU7DP5aU6A8Ns2', 'admin') 
2016-11-22 23:13:44 Debug: duration=0 rows=0 SELECT 1 AS `existing` FROM user_profiles UserProfiles WHERE UserProfiles.user_id = 11 LIMIT 1 
2016-11-22 23:13:44 Debug: duration=0 rows=1 SELECT 1 AS `existing` FROM users Users WHERE Users.id = 11 LIMIT 1 
2016-11-22 23:13:44 Debug: duration=0 rows=0 INSERT INTO user_profiles (user_id, address_one, address_two, age, sex, first_name, last_name, city, state, zip, phone, photo) VALUES (11, 'Test Place 42', 'Teeeeeeest', 24, 'm', 'Kyle', 'Person', 'Place', 'FL', '12312', '1231231234', '') 
2016-11-22 23:13:44 Debug: duration=0 rows=0 ROLLBACK 

所以，看来INSERT INTO user_profiles语句正确选择（在这种情况下为11），但是我在互联网上读到的所有内容都表示它可能无法通过id 11找到用户。CakePHP在我的***中非常痛苦，并且隐藏了可变数据代码从我的错误，说我的SQL查询是：

INSERT INTO user_profiles (user_id, address_one, address_two, age, sex, first_name, last_name, city, state, zip, phone, photo) VALUES (:c0, :c1, :c2, :c3, :c4, :c5, :c6, :c7, :c8, :c9, :c10, :c11) 

因此，如果有人知道如何阅读这些“c变量”，那么我会想象一下，这将有很大的帮助。我不擅长调试，所以请随时推荐我可以用来提高生产力的任何方法。

这是构建两个表的SQL代码：

SET @OLD_UNIQUE_CHECKS=@@UNIQUE_CHECKS, UNIQUE_CHECKS=0; 
SET @OLD_FOREIGN_KEY_CHECKS=@@FOREIGN_KEY_CHECKS, FOREIGN_KEY_CHECKS=0; 
SET @OLD_SQL_MODE=@@SQL_MODE, SQL_MODE='TRADITIONAL,ALLOW_INVALID_DATES'; 

CREATE SCHEMA IF NOT EXISTS `staging` DEFAULT CHARACTER SET utf8 ; 
USE `staging` ; 

DROP TABLE IF EXISTS `staging`.`users` ; 

CREATE TABLE IF NOT EXISTS `staging`.`users` (
    `id` INT NOT NULL AUTO_INCREMENT, 
    `email` VARCHAR(255) NOT NULL, 
    `password` VARCHAR(128) NOT NULL, 
    `role` ENUM('admin', 'vet', 'client') NOT NULL, 
    PRIMARY KEY (`id`)); 

DROP TABLE IF EXISTS `staging`.`user_profiles` ; 

CREATE TABLE IF NOT EXISTS `staging`.`user_profiles` (
    `user_id` INT NOT NULL, 
    `address_one` VARCHAR(255) NULL, 
    `address_two` VARCHAR(255) NULL, 
    `age` INT NULL, 
    `sex` ENUM('m', 'f') NULL, 
    `first_name` VARCHAR(45) NULL, 
    `last_name` VARCHAR(45) NULL, 
    `city` VARCHAR(45) NULL, 
    `state` VARCHAR(45) NULL, 
    `zip` VARCHAR(6) NULL, 
    `phone` VARCHAR(45) NULL, 
    `photo` VARCHAR(255) NULL, 
    PRIMARY KEY (`user_id`), 
    INDEX `fk_user_profiles_users2_idx` (`user_id` ASC), 
    CONSTRAINT `fk_user_profiles_users` 
    FOREIGN KEY (`user_id`) 
    REFERENCES `staging`.`users` (`id`) 
    ON DELETE CASCADE 
    ON UPDATE CASCADE) 
ENGINE = InnoDB; 

SET SQL_MODE=@OLD_SQL_MODE; 
SET FOREIGN_KEY_CHECKS=@OLD_FOREIGN_KEY_CHECKS; 
SET UNIQUE_CHECKS=@OLD_UNIQUE_CHECKS; 

这是由MySQLWorkbench产生。

非常感谢你的时间和帮助！

Answer 1

这不再是一个PHP问题。现在要解雇我的问题。