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我使用loadApprovers()函数从后端通过不同的数组获取用户的名称和相应电子邮件。我想在选择用户名时将用户电子邮件提交给后端。我在select元素中使用了ng-options。在ng选项中定义值属性
HTML:
<div class="groups list list-insert" ng-init='request.loadApprover()'>
<label for="approver1_name" class="item item-input">
<select ng-options="item as item.approver1_name for item in request.approver1_email track by item.id" ng-model="request.approvalObject.approver1_email" ></select>
控制器:
constructor($http, $scope, socket) {
this.$http = $http;
console.log("testentry");
this.approver1_email=[];
this.approver1_name=[];
}
loadApprover($http, approver1_email, approver1_name) {
this.$http.get('/api/approvals', approver1_email, approver1_name)
.then((data) => {
console.log(data.data)
this.approver1_email=data.data;
})
}
我无法提交用户的电子邮件时,我选择的用户名。我是AngularJS的初学者,除此之外,我无法再了解如何编写ng-options。有人可以指导我如何编写更好的代码来完成此任务?
如果你只是想的电子邮件属性选择的对象,你可以做'ng-options =“item.email as item.approver1_name ...”' – devqon