PHP推入数组

我有一个PHP循环从我的表中获取数据并将其推入数组。PHP推入数组

$children = mysql_query("SELECT c.id, c.name, c.age, c.photoName, c.panelColor FROM children as c"); 
$temp = array(); 

while ($child = mysql_fetch_assoc($children)) { 

    // Get the child's reatings 
    $ratings = mysql_query(' 
     SELECT r.behaviourID, t.points, t.typeName 
     FROM behaviourRatings as r 
     JOIN behaviourTypes as t 
     ON r.behaviourID = t.typeID 
     WHERE r.childID = ' . $child['id']); 

    // Loop over the ratings 
    $totalPoints = 0; 
    while ($childRatings = mysql_fetch_array($ratings)){ 
     $totalPoints = ($totalPoints + $childRatings['points']); 
    } 

    // We can only max out at our set max 
    if(($totalPoints + $maxPoints) > $maxPoints) { 
     $total = $maxPoints; 
    } else if($totalPoints < 0){ 
     $total = ($maxPoints + $totalPoints); 
    }else{ 
     $total = ($maxPoints - $totalPoints); 
    } 

    // Set the child array 
    $temp[] = $child; 
} 

$response = array(); 
$response['timestamp'] = $currentmodif; 
$response['children'] = $temp; 
echo json_encode($response, JSON_PRETTY_PRINT);

我想添加其他键/值对称为points数组，并指定其为$total值。

我试过做$temp['points'] = $total，但它把它放在数组之外，而不是与外部循环数据。

这是函数的结果：

{ 
    "timestamp": 1482918104, 
    "children": [ 
     { 
      "id": "1", 
      "name": "Maya", 
      "age": "5", 
      "photoName": "maya.png", 
      "panelColor": "" 
     }, 
     { 
      "id": "2", 
      "name": "Brynlee", 
      "age": "3", 
      "photoName": "brynlee.png", 
      "panelColor": "green" 
     } 
    ] 
}

我想告诉每一个这些儿童的点，但我不能确定如何将它添加到阵列的一部分。通过让所有孩子的收视率在一个查询

$child['points'] = $total; 
$temp[] = $child;

来源

2016-12-29 SBB

不要使用任何的'mysql_'功能。他们在几年前被弃用，并从PHP 7起正式删除。 –

@AndyIbanez - 谢谢，我会研究这一点。 I – SBB

你应该把它添加到$child变，只是增加该变量的$temp阵列之前。

事情是这样的：

$children = mysql_query("SELECT c.id, c.name, c.age, c.photoName, c.panelColor FROM children as c"); 

$childrenIds = []; 

while ($child = mysql_fetch_assoc($children)) { 
    $childrenIds[] = $child['id']; 
} 

if (!empty($childrenIds)) { 
    $ratings = mysql_query(' 
     SELECT r.behaviourID, t.points, t.typeName 
     FROM behaviourRatings as r 
     JOIN behaviourTypes as t 
     ON r.behaviourID = t.typeID 
     WHERE r.childID IN (' . implode(',', $childrenIds) . ')'); 
}

来源

2016-12-29 01:21:51 Dekel

grr，这么简单：/我一直试图将它添加到temp，没想到将它添加到子数组。将很快接受:) – SBB

发生在每个人:)你有我的投票在那里保持问题清洁和明确！ – Dekel

你也可以请求减少数据库：

来源

2016-12-29 04:13:15

PHP推入数组

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