1
我有一个Canvas
作为我的应用程序的基础,它有几个控件,用户可以使用它们各自的ManipulationDelta
's来移动,旋转和缩放。在屏幕边界内限制控制/ UIElement
问题是,用户可能会意外地将控件移出Canvas
或屏幕边界,同时用手指移动控件。
如何限制这些控件在Canvas
内的移动?
我有一个Canvas
作为我的应用程序的基础,它有几个控件,用户可以使用它们各自的ManipulationDelta
's来移动,旋转和缩放。在屏幕边界内限制控制/ UIElement
问题是,用户可能会意外地将控件移出Canvas
或屏幕边界,同时用手指移动控件。
如何限制这些控件在Canvas
内的移动?
您可以在WinRT XAML Toolkit中检查ToolWindow
控件和FlickBehavior
以获取灵感。
这是非常基本的整体。如果你不这样做惯性,可能是这样的:
if (x < 0)
x = 0;
if (x > _canvas.ActualWidth - this.AssociatedObject.ActualWidth)
x = _canvas.ActualWidth - this.AssociatedObject.ActualWidth;
if (y < 0)
y = 0;
if (y > _canvas.ActualHeight - this.AssociatedObject.ActualHeight)
y = _canvas.ActualHeight - this.AssociatedObject.ActualHeight;
一旦你旋转或缩放 - 你需要做一些矩阵变换操作,以获得边框。幸运的是,该平台有一些方法可以让你更容易 - 即TransformToVisual()
和TransformPoint()
方法。我也有一个辅助类,使用en扩展方法,使它更容易 - 检查出VisualTreeHelperExtensions.GetBoundingRect()
。
/// <summary>
/// Gets the bounding rectangle of a given element
/// relative to a given other element or visual root
/// if relativeTo is null or not specified.
/// </summary>
/// <remarks>
/// Note that the bounding box is calculated based on the corners of the element relative to itself,
/// so e.g. a bounding box of a rotated ellipse will be larger than necessary and in general
/// bounding boxes of elements with transforms applied to them will often be calculated incorrectly.
/// </remarks>
/// <param name="dob">The starting element.</param>
/// <param name="relativeTo">The relative to element.</param>
/// <returns></returns>
/// <exception cref="System.InvalidOperationException">Element not in visual tree.</exception>
public static Rect GetBoundingRect(this FrameworkElement dob, FrameworkElement relativeTo = null)
{
if (DesignMode.DesignModeEnabled)
{
return Rect.Empty;
}
if (relativeTo == null)
{
relativeTo = Window.Current.Content as FrameworkElement;
}
if (relativeTo == null)
{
throw new InvalidOperationException("Element not in visual tree.");
}
if (dob == relativeTo)
{
return new Rect(0, 0, relativeTo.ActualWidth, relativeTo.ActualHeight);
}
var ancestors = dob.GetAncestors().ToArray();
if (!ancestors.Contains(relativeTo))
{
throw new InvalidOperationException("Element not in visual tree.");
}
var topLeft =
dob
.TransformToVisual(relativeTo)
.TransformPoint(new Point());
var topRight =
dob
.TransformToVisual(relativeTo)
.TransformPoint(
new Point(
dob.ActualWidth,
0));
var bottomLeft =
dob
.TransformToVisual(relativeTo)
.TransformPoint(
new Point(
0,
dob.ActualHeight));
var bottomRight =
dob
.TransformToVisual(relativeTo)
.TransformPoint(
new Point(
dob.ActualWidth,
dob.ActualHeight));
var minX = new[] { topLeft.X, topRight.X, bottomLeft.X, bottomRight.X }.Min();
var maxX = new[] { topLeft.X, topRight.X, bottomLeft.X, bottomRight.X }.Max();
var minY = new[] { topLeft.Y, topRight.Y, bottomLeft.Y, bottomRight.Y }.Min();
var maxY = new[] { topLeft.Y, topRight.Y, bottomLeft.Y, bottomRight.Y }.Max();
return new Rect(minX, minY, maxX - minX, maxY - minY);
}
一旦你的边界RECT - 您可以使用它的尺寸,而不是被操纵的对象ActualWidth
/ActualHeight
和X & y以确定它可以或不可以去。
是的,这是控件与屏幕边界对齐时的作品。但是,当控件旋转一个角度时,将'ActualWidth'添加到'x',其中x是左上角的点不会给出右上角的点。 – 2014-09-26 05:16:42
我已经更新了我对这种情况的回答。 – 2014-09-26 15:05:42
这很好! – 2014-09-30 02:44:19