如何使用ExchangeService访问共享邮箱（Outlook 2013）

Question

我正尝试使用ExchangeService访问Outlook中的第二个邮箱。但是当我运行该应用程序时，它抓住了我的主要电子邮件。值得注意的是，我在这里使用Windows身份验证，并且我需要这个工作。

var useExchangeServer = new UseExchangeServer("SECONDEMAIL@mycompany.com"); 
var messages = useExchangeServer.LoadMessages(1); 

foreach (var message in messages){ //At this point message has the wrong email... 
... 
} 

这里是我的“UseExchangeServer”类

public UseExchangeServer(string mailBox) 
    { 
     _service = new ExchangeService(ExchangeVersion.Exchange2010_SP2); 
     _service.UseDefaultCredentials = true; 
     _service.AutodiscoverUrl(mailBox); 
    } 

public FindItemsResults<Item> GetLastItems(int numberOfItems) 
    { 
     return _service.FindItems(WellKnownFolderName.Inbox, new ItemView(numberOfItems)); 
    } 

public IEnumerable<EmailMessage> LoadMessages(int numberOfMessages) 
    { 
     var findResults = GetLastItems(numberOfMessages); 

     foreach (var item in findResults.Items) 
     { 
      var message = EmailMessage.Bind(_service, item.Id, new PropertySet(BasePropertySet.IdOnly, ItemSchema.Attachments)); 
      message.Load(); 
      yield return message; 
     } 
    } 

Answer 1

您需要使用FolderId超载指定要以任何方式进入属于您正在使用将要使用的凭据的邮箱的邮箱所以你需要做的是这样的与您的代码如下

public UseExchangeServer(string mailBox) 
{ 
    _service = new ExchangeService(ExchangeVersion.Exchange2010_SP2); 
    _service.UseDefaultCredentials = true; 
    _service.AutodiscoverUrl(mailBox); 
} 

public FindItemsResults<Item> GetLastItems(int numberOfItems,string mailBox) 
{ 
    FolderId FolderToAccess = new FolderId(WellKnownFolderName.Inbox,mailBox); 
    return _service.FindItems(FolderToAccess, new ItemView(numberOfItems)); 
} 

public IEnumerable<EmailMessage> LoadMessages(int numberOfMessages) 
{ 
    var findResults = GetLastItems(numberOfMessages); 

    foreach (var item in findResults.Items) 
    { 
     var message = EmailMessage.Bind(_service, item.Id, new PropertySet(BasePropertySet.IdOnly, ItemSchema.Attachments)); 
     message.Load(); 
     yield return message; 
    } 
} 

干杯 格伦