使用GSON解析json数据源

Question

我有一个简单的JSON源，它返回一个图像路径和一组协调。 “坐标”可以有无限的协调。在我下面的例子中，它只有3组。

{"image":"Some data", "coords": {"0":[0,0], "1":[55,22], "2":[46,65]}} 

我将如何使用GSON来解析此问题？我如何为此创建课程？

感谢

Answer 1

你将有一个坚硬的 因为它不是有效的JSON。

http://jsonlint.com/

如果它是有效的JSON，如...

{"image":"Some data", "coords": {"0":[0,0], "1":[55,22], "2":[46,65]}}

我相信GSON可以解析coords到<String, ArrayList<Integer>>一个map但我需要尝试，以确保。

Answer 2

添加gson-1.7.1.jar文件，并写入这个类来获得所需要的JSONObject或JSONArray从URL。

public class GetJson { 

    public JSONArray readJsonArray(String url) { 

     String read = null; 
     JSONArray mJsonArray = null; 
     try { 
      HttpClient http = new DefaultHttpClient(); 
      HttpPost post = new HttpPost(url); 
      HttpResponse response = http.execute(post); 
      HttpEntity entity = response.getEntity(); 
      InputStream is = entity.getContent(); 

      BufferedReader br = new BufferedReader(new InputStreamReader(is)); 
      StringBuilder builder = new StringBuilder(); 
      String str = null; 
      while ((str = br.readLine()) != null) { 
       builder.append(str); 
      } 
      is.close(); 
      read = builder.toString(); 
      mJsonArray = new JSONArray(read); 
     } catch (Exception e) { 
      e.printStackTrace(); 
     } 
     return mJsonArray; 
    } 

    public JSONObject readJsonObject(String url) { 
     String read = null; 
     JSONObject mJsonObject = null; 
     try { 
      HttpClient http = new DefaultHttpClient(); 
      HttpPost post = new HttpPost(url); 
      HttpResponse response = http.execute(post); 
      HttpEntity entity = response.getEntity(); 
      InputStream is = entity.getContent(); 

      BufferedReader br = new BufferedReader(new InputStreamReader(is)); 
      StringBuilder builder = new StringBuilder(); 
      String str = null; 
      while ((str = br.readLine()) != null) { 
       builder.append(str); 
      } 
      is.close(); 
      read = builder.toString(); 
      mJsonObject = new JSONObject(read); 
     } catch (Exception e) { 
      e.printStackTrace(); 
     } 
     return mJsonObject; 
    } 
} 

享受...

然后解析JSON看到这些教程，

Tutorial 1

Tutorial 2

Tutorial 3